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4 years ago

6

Which type of study contains a treatment?

2 answers:

Radda [10]4 years ago

7 0

Typically, in an experiment there are two groups. One group is called the control group. The other group is the experimental group. This second group receives some sort of treatment. The control group does not. The idea is to see if the treatment has an effect on those who receive it by comparing them to a comparable group that does not receive the treatment.

So the answer is experiment.

luda_lava [24]4 years ago

3 0

The type of study that contains a treatment is called EXPERIMENTAL STUDY.
An experimental set up usually involved random assignment of variables into different group and manipulation of a particular variable while others are controlled. This type of study is usually done to determine the effect of one variable on the outcome of another variable. The experimental set up is usually made up of control and treatment groups.

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wolverine [178]

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Step-by-step explanation:

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3 years ago

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Easiest way to do this is to turn them all to decimals

√5= 2.23
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3 years ago

25x2 + 16 – 40x – 64y

Sedaia [141]

Answer:

25x2 - 40x - 64y + 16

Step-by-step explanation:

Step 1 :

Equation at the end of step 1 :

((52x2 + 16) - 40x) - 64y

Step 2 :

Final result :

25x2 - 40x - 64y + 16

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4 years ago

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Goryan [66]

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3 years ago

Read 2 more answers

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Ann [662]

Answer:

10010

Step-by-step explanation:

$1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$111=1(2)^2+1(2)^1+1(2)^0$

So $1011+111$ gives us:

$1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$+$

$1(2)^2+1(2)^1+1(2)^0$

-----------------------------------------------------

Combine like terms:

$1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0$

$1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0$

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace $2^0$ with 1 and $2$ with $(2)^1$ :

$1(2)^3+1(2)^2+(2)^2+(2)^1(1)$

I want a $2^0$ number:

$1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0$

Combine like terms:

$1(2)^3+2(2)^2+1(2)^1+0(2)^0$

$2(2)^2=2^3$ :

$1(2)^3+2^3+1(2)^1+0(2)^0$

Combine like terms:

$2(2)^3+1(2)^1+0(2)^0$

We can rewrite the first term by law of exponents:

$2^4+1(2)^1+0(2)^0$

$1(2)^4+1(2)^1+0(2)^0$

So the binary form is:

$10010$

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

1 0 1 1

+ 1 1 1

------------------------------

(1) (1) (1)

1 0 1 1

+ 1 1 1

------------------------------

1 0 0 1 0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

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3 years ago