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cricket20 [7]
3 years ago
12

Which situation is an example of an observational study?

Mathematics
1 answer:
stiks02 [169]3 years ago
8 0

Answer:

D.) Collecting the cholesterol readings of a group of people in a certain age group in a small town

Step-by-step explanation:

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Which equation correctly uses the law of cosines to solve for y? 92 = y2 + 192 – 2(y)(19)cos(41°) y2 = 92 + 192 – 2(y)(19)cos(41
FrozenT [24]
Answer: Fourth option: y^2=9^2+19^2-2(9)(19) cos(41°)

The law of cosines to solve for one side is:
c^2=a^2+b^2-2ab cos C
We must know the other two sides (a and b) and the angle between these sides (angle C, the opposite to the side that we want to determine)

In this case c=y, a=9, b=19, and C=41°, then:
y^2=9^2+19^2-2(9)(19) cos (41°)
3 0
3 years ago
Read 2 more answers
In the fraction 35/10 what is the product that lies between
RUDIKE [14]
The result of the fraction is 3.5

we can calculate this like this:
\frac{35}{10} = \frac{5*7}{2*5} = \frac{7}{5}=3.5

I think that the question is asking between which two natural numbers the result lies, and the result is 3 and 4: it's bigger than 3 and smaller than 4

 
8 0
3 years ago
Find the value of x.
N76 [4]
These triangles are congruent because of SAS so therefore 3x-5 =2x+1 and x=6
4 0
3 years ago
PLZ Help!!!<br> Look at the pic.
stealth61 [152]
435 being the constant means that is what they started with

Hope this helps :)
8 0
3 years ago
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If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?
Oduvanchick [21]
Remember that (g-f)(x) is g(x)-f(x). We know form our problem that f(x)=4-x^2 and g(x)=6x, so:
(g-f)(x)=g(x)-f(x)
(g-f)(x)=6x-(4-x^2)
(g-f)(x)=6x-4+x^2

Now, to find (g-f)(3), we just need to evaluate (g-f)(x) at 3. In other words, we are going to replace x with 3:
(g-f)(x)=6x-4+x^2
(g-f)(x)=6(3)-4+(3)^2

We can conclude that the correct answer is <span>C.6(3) – 4 + 3^2 </span>

5 0
3 years ago
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