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Andreyy89
3 years ago
7

I need the solution

Mathematics
1 answer:
Nataly [62]3 years ago
5 0

The only thing you can do here is to try to simplify, so I'll assume that's what you want to do.

\dfrac{b^2-a^2}{2a^2+ab-3b^2}

The numerator is a difference of squares, so it's easy to factorize:

b^2-a^2=(b-a)(b+a)

In the denominator, we factorize by grouping:

2a^2+ab-3b^2=2a^2-2ab+3ab-3b^2=2a(a-b)+3b(a-b)=(2a+3b)(a-b)

So we have

\dfrac{b^2-a^2}{2a^2+ab-3b^2}=\dfrac{(b-a)(b+a)}{(2a+3b)(a-b)}=-\dfrac{b+a}{2a+3b}

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Answer:

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Step-by-step explanation:

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