63+12x<15
12x<-48 (subtract 63 from both sides)
x<-4 (divide out the 12)
Answer:
∠EFG = 48°
Step-by-step explanation:
As FH bisects ∠EFG , ∠EFH = ∠HFG .
We know that ∠EFH = (-5x + 89)° . So ∠HFG = ∠EFH = (-5x + 89)°
Also, ∠HFG + ∠EFH = ∠EFG
=> 2(-5x + 89)° = (61 - x)°
=> -10x + 178 = 61 - x
=> 10x - x = 178 - 61
=> 9x = 117
=> x = 117 / 9 = 13
Putting the value of 'x' in ∠EFG gives :-
(61 - x)° = (61 - 13)° = 48°
Answer:
. y2 = 12x 40:12 :3 2. x² = -8y 408 3. (x + 2)2 = -4(y-1). \(-2,1) opens v. F-2,0) ... F (0:2). V(0,-2). F(4,2)
Step-by-step explanation:
