Answer:
∠2 = 18°
Step-by-step explanation:
∠WXZ = ∠1 + ∠2 ← substitute ∠1 = 3∠2
∠WXZ = 3∠2 + ∠2, that is
72 = 4∠2 ( divide both sides by 4 )
18 = ∠2, that is
∠2 = 18°
23x-13=2(x+2)
First you would distribute the 2 into the parenthesis
It will look like this after: 23x-13=2x+4
Then you would subtract 2x on both sides because u have to get the x's on one side
It will look like this after:21x-13=4
Then you would add 13 to both sides
It will look like this after: 21x=17
Then you would divide 21 on both sides
Your final product is 21/17
48 gallons... since the first shower head gives 9 gallons per minute you multiply 9 by 8 then you use the equation and multiply 3 by 8 then you subtract the two shower heads
Answer:
The answer is "Option A and Option B"
Step-by-step explanation:
In question 1:
The fixed cost=2621.21
The unit variable cost=35.58
Calculating the total cost for 45 boat slips:
In question 2:
It is the pure fixed costs that remain consistent in total regardless of dynamic loads. An overall cost B both for 1000 and 2000 unit is unchanged, therefore the Cost B is a fixed sum.
he magician starts with the birthday boy and moves clockwise, passing out 100100100100 pieces of paper numbered 1111 through 100100100100. He cycles around the circle until all the pieces are distributed. He then uses a random number generator to pick an integer 1111 through 100100100100, and chooses the volunteer with that number.
Method2: The magician starts with the birthday boy and moves counter-clockwise, passing out 75757575 pieces of paper numbered 1111 through 75757575. He cycles around the circle until all the pieces are distributed. He then uses a random number generator to pick an integer 1111 through 75757575, and chooses the volunteer with that number.
Method 3\: The magician starts with the birthday boy and moves clockwise, passing out 30303030 pieces of paper numbered 1111 through 30303030. He cycles around the circle until all the pieces are distributed. He gives #1111 to the birthday boy, #2222 to the next kid, and so on. He then counts the number of windows in the room and chooses the volunteer with that number.
yes probabilites can be used to make fair ones
thanx
heya
