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HACTEHA [7]
3 years ago
10

How do I solve this?

Mathematics
1 answer:
Ivenika [448]3 years ago
7 0

\overline{XS}\cong\overline{YT}\Rightarrow 3m+7=4.2m+5\ \ \ |-7\\\\3m=4.2m-2\ \ \ \ |-4.2m\\\\-1.2m=-2\ \ \ \ |:(-1.2)\\\\m=\dfrac{2}{1.2}\\\\m=\dfrac{20}{12}\\\\m=\dfrac{5}{3}\to m=1\dfrac{2}{3}


\overline{YS}\cong\overline{XT}\Rightarrow3\dfrac{1}{2}r+2=2r+5\ \ \ \ |-2\\\\3\dfrac{1}{2}r=2r+3\ \ \ \ |-2r\\\\1\dfrac{1}{2}r=3\ \ \ |\cdot2\\\\3r=6\ \ \ \ |:3\\\\r=2

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The formula for the chord length is 2r*sin(c/2), with c being the angle between the two points on the circle (in this case, ∠QOR=∠NOR).. Our radius is 5, so the length of chord NR is 2*5*sin(60/2)=5, making our answer 5(ON)+5(OR)+5(RN)

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Step-by-step explanation:

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Pleas help me solve #1 :( <br> Your answer helps so much!!
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ANSWER

y = 7 \sqrt{2}

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EXPLANATION

The given triangle has a right angle.

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Recall the mnemonics TOA, which means,

\tan(45 \degree)  =  \frac{opposite}{adjacent}

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To find y, we use the sine ratio, which means

\sin(45 \degree)  =  \frac{opposite}{hypotenuse}

\sin(45 \degree)  =  \frac{7}{y}

y=  \frac{7}{\sin(45 \degree) }

y=  \frac{7}{ \frac{1}{ \sqrt{2} } }

y = 7 \times  \frac{ \sqrt{2} }{1}

y = 7 \sqrt{2}

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Step-by-step explanation:

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