Given,
The sum of three integers is 92
So,
Let,
The first integer be "x"
The second integer be "y"
The third integer be "z"
Now,
According to the question,
y = 3x ..............equation (1)
z = 2x - 10 .............. equation (2)
x + y + z = 92 ..............equation (3)
Now,
Substituting the value of "y" and "z" from equation (1) and (2), we get,
x + (3x) + (2x - 10) = 92
x + 3x + 2x - 10 = 92
6x - 10 = 92
6x = 92 + 10
x = 102 / 6
x = 17
Now,
substituting the value of "x" in equation (1)
y = 3 (17)
y = 51
Now,
Substituting the value of "x" in equation (2),
z = 2 (17 ) - 10
z = 34 - 10
z = 24
So, the numbers are 17, 51 and 24
NEVER HATE MATH!!!
The factored form would be (3x-9)(x-1)
The picture should help a bit
The value of x is 6 in the equation.
Step-by-step explanation:
Given equation is;

Taking least common multiple

Multiplying both sides by 6

Dividing both sides by 5

The value of x is 6 in the equation.
Keywords: linear equation, fraction
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Answer:
2 pairs of opposite parallel sides is parallelogram