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posledela
3 years ago
6

Please help me solve these proportions

Mathematics
2 answers:
Genrish500 [490]3 years ago
7 0

\frac{5 \times 5}{8 \times 5}  =  \frac{y}{40}  \\ y = 25

\frac{g \div 7}{56 \div 7}  =  \frac{2}{8}  \\ g = 7 \times 2 = 14

y = 25, g = 14

Hope this helps. - M
Anvisha [2.4K]3 years ago
4 0
For the first one y=25

For the second one y=14
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Which function is a quadratic function? a(x) = –2x^3 + 2x – 6 b(x) = 5x^3 + 8x^2 + 3 c(x) = –8x^2 + 3x – 5 d(x) = 6x^4 + 2x – 3
Sedaia [141]

Answer:

c(x) = –8x^2 + 3x – 5 is a quadratic

Step-by-step explanation:

A quadratic function involves the 2nd power of x:  x^2, and may (or may not) involve the 1st and zeroth power of x.

a(x) = -2x^3 is not a quadratic because of that exponent 3; in a quadratic, the highest power is always 2.

b(x) = 5x^3 + 8x^2 + 3 is not a quadratic for the same reason that a(x) is not a quadratic.

c(x) = –8x^2 + 3x – 5 is a quadratic:  the highest power of x is x^2, the other powers are x^1 and x^0.

5 0
4 years ago
Find the equation of the line that passes through points a and b. <br> Please help.
Fiesta28 [93]

Answer:

y=2x-1

Step-by-step explanation:

Gradient : (7-3) / (4-2) = 2

y=2x+c

substitute one of the points

3=2*2+c

c=-1

y=2x-1

5 0
3 years ago
How do you find the length inside a cube diagonally???
MrRissso [65]
Solution:

We have: In the attached image, observe rectangle triangle ΔBAD
Use the Pythagorean Theorem:
BD = √(AB² + AD²)
BD = √(2² + 4²)
BD = √(4 + 16)
BD = √20

In the attached image, observe rectangle triangle ΔBDH
Use the Pythagorean Theorem:
BH = √(BD² + DH²)
BH = √(√20² + 5²)
BH = √(20 + 25)
BH = √45
BH = √(9 × 5)
BH = √9 × √ 5
BH = 3√5
BH = 3 × 2.24

BH = 6.72 cm

4 0
4 years ago
Childe, needs help please
OLEGan [10]
I don’t know the first part but i think the second part would be 4^11
3 0
3 years ago
Find the exact value of csc 5pi/6
Leona [35]

Answer:

csc 2 (csc \frac{5\pi}{6} = csc 150 = csc 30 = csc 2)

Step-by-step explanation:

csc \frac{5\pi}{6} is in the 2nd Quadrant where only sin, and csc are positive.

csc (\frac{5\pi}{6})=csc (\pi -(\frac{5\pi}{6}))=csc(\frac{5\pi}{6})

but csc \frac{5\pi}{6} = \frac{1}{sin (\pi/6)} = \frac{1}{sin 30} = \frac{1}{1/2} =2

7 0
3 years ago
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