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OLEGan [10]
3 years ago
13

How many permutations can be made of the letters of the word "radar" when taken all at a time?

Mathematics
2 answers:
n200080 [17]3 years ago
3 0
Slot method
5 letters
1st slot=5 options
2nd slot=4 options (1 went ot first slot)
3rd slot=3 options (1 went to 2nd)
4th slot=2 options
5th slot=1 option

5*4*3*2*1=120 ways
Iteru [2.4K]3 years ago
3 0

Answer:

Total number of permutations which can be made = 120

Step-by-step explanation:

The word is given to be : RADAR

Number of letters in the given word = 5

The letters are taken all at a time

⇒ Repetition of the letters are not allowed

Now, Number of possibilities for the first letter = 5

Number of possibilities for the second letter = 4

Number of possibilities for the third letter = 3

Number of possibilities for the forth letter = 2

Number of possibilities for the five letter = 1

Hence, Total number of permutations which can be made = 5 × 4 × 3 × 2 × 1  

= 120

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Solve the following equation simultaneously 1/x-5/y=7, 2/x+1/y=3​
maria [59]

Answer:

  (x, y) = (1/2, -1)

Step-by-step explanation:

Subtracting twice the first equation from the second gives ...

  (2/x +1/y) -2(1/x -5/y) = (3) -2(7)

  11/y = -11 . . . . simplify

  y = -1 . . . . . . . multiply by y/-11

Using the second equation, we can find x:

  2/x +1/-1 = 3

  2/x = 4 . . . . . . . add 1

  x = 1/2 . . . . . . . multiply by x/4

The solution is (x, y) = (1/2, -1).

_____

<em>Additional comment</em>

If you clear fractions by multiplying each equation by xy, the problem becomes one of solving simultaneous 2nd-degree equations. It is much easier to consider this a system of linear equations, where the variable is 1/x or 1/y. Solving for the values of those gives you the values of x and y.

A graph of the original equations gives you an extraneous solution of (x, y) = (0, 0) along with the real solution (x, y) = (0.5, -1).

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Simplify: -1/2 (-5/6 + 1/3)
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Step-by-step explanation:

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Liana's class was going on a very exciting school trip, but when Liana got to school, the school bus had already left! Frantic,
Llana [10]

Answer:

  • <u>They can catch up with the bus at 10:40 am.</u>

Explanation:

1. Set the time when Liana and her mother can leave (8:40 am) as t₀ = 0; thus the time of driving for them will be t.

2. The average speed at whic Liana's mother drive: 60 miles/hour

3. Thus, the distance they will have driven will be:

  • distance = average speed × time = 60t

4. The time the bus left was 8:00 am, which is 40 minutes before Liana and her mom can leave.

Thus, the time wil have driven when Liana and her mom have driven t hours  minutes will be: t + 40 min / 60 min/ hour = t + 2/3

5. The average speed of teh bus is 45 miles / hour

6. The distance the bus will have driven will be:

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7. When Liana and her mother catch up with the bus, the distances driven by both of them are equal:

  • 60t = 45(t + 2/3)
  • 60t = 45t + 30
  • 60t - 45t = 30
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Thus, Liana and her mom can catch up with the bus after 2 hours, since 8:40 am; this is, 10:40 am.

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4 years ago
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