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3 years ago

Which of the following is the equation of a line perpendicular to the line y =

Mathematics

1 answer:

babunello [35]3 years ago

8 0

Answer:

y - 7 = (1/10)(x - 5)

Step-by-step explanation:

Next time please share the possible answers. Thank you.

Any line perpendicular to y = -10x + 1 has the slope +1/10, which is the negative reciprocal of -10.

Using the point-slope formula, we get:

y - 7 = (1/10)(x - 5)

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How do we write ordered pairs?

kvv77 [185]

Answer:

find the x and y values

Step-by-step explanation:

Ordered pairs are often used to represent two variables. we write (x, y) The number which corresponds to the value of x is called the x-coordinate and the number which corresponds to the value of y is called the y-coordinate.

Hope this helps

7 0

3 years ago

I’m stuck can some one help me

abruzzese [7]

Answer:

3) Midpoint is (-4,0.5)

Option A is correct.

4) Midpoint is (2.5,0)

Option B is correct.

5) The factors are (x+4)(x-7)

Option C is correct.

6) The factors are (x+4)(x+2)

Option A is correct.

Step-by-step explanation:

Question 3

Find midpoint of the following:

(2,-7), (-10,8)

The formula used to find midpoint is: $Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )$

We have $x_1=2, y_1=-7, x_2=-10,y_2=8$

Putting values and finding midpoint

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2-10}{2},\frac{-7+8}{2} )\\Midpoint=(\frac{-8}{2},\frac{1}{2} )\\Midpoint=(-4,0.5 )$

So, Midpoint is (-4,0.5)

Option A is correct.

Question 4

Find midpoint of the following:

(2,-10), (3,10)

The formula used to find midpoint is: $Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )$

We have $x_1=2, y_1=-10, x_2=3,y_2=10$

Putting values and finding midpoint

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} )\\Midpoint=(\frac{2+3}{2},\frac{-10+10}{2} )\\Midpoint=(\frac{5}{2},\frac{0}{2} )\\Midpoint=(2.5,0 )$

So, Midpoint is (2.5,0)

Option B is correct.

Question 5

Factor each completely

$x^2-3x-28$

We will break the middle term and find factors

$x^2-3x-28\\=x^2-7x+4x-28\\Taking\:common\\=x(x-7)+4(x-7)\\=(x+4)(x-7)$

So, the factors are (x+4)(x-7)

Option C is correct.

Question 6

Factor each completely

$x^2+6x+8$

We will break the middle term and find factors

$x^2+6x+8\\=x^2+4x+2x+8\\=x(x+4)+2(x+4)\\=(x+4)(x+2)$

So, the factors are (x+4)(x+2)

Option A is correct.

7 0

3 years ago

1 A square is a rectangle.

irinina [24]

1.sometimes
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3 0

3 years ago

Read 2 more answers

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3 years ago

A Find the amount compounded annually on Rs 25,000 for 2 years if the rates of

STatiana [176]

Answer:

Amount = Rs. 30250 when Rate = 10%

Amount = Rs. 31360 when Rate = 12%

Step-by-step explanation:

Given

$Principal, P = Rs.\ 25,000$

$Time, t = 2\ years$

$Rate; R_1 = 10\%$

$Rate; R_2 = 12\%$

Number of times (n) = Annually

$n = 1$

Required

Determine the Amount for both Rates

Amount (A) is calculated by:

$A = P(1 + \frac{r}{n})^{nt}$

When Rate = 10%, we have:

Substitute 25,000 for P; 2 for t; 1 for n and 10% for r

$A = 25000 * (1 + \frac{10\%}{1})^{1 * 2}$

$A = 25000 * (1 + \frac{10\%}{1})^{2}$

$A = 25000 * (1 + 10\%)^{2}$

Convert 10% to decimal

$A = 25000 * (1 + 0.10)^{2}$

$A = 25000 * (1.10)^{2}$

$A = 25000 * 1.21$

$A = 30250$

Hence;

Amount = Rs. 30250 when Rate = 10%

When Rate = 12%, we have:

Substitute 25,000 for P; 2 for t; 1 for n and 10% for r

$A = 25000 * (1 + \frac{12\%}{1})^{1 * 2}$

$A = 25000 * (1 + \frac{12\%}{1})^{2}$

$A = 25000 * (1 + 12\%)^{2}$

Convert 12% to decimal

$A = 25000 * (1 + 0.12)^{2}$

$A = 25000 * (1.12)^{2}$

$A = 25000 * 1.2544$

$A = 31360$

Hence;

Amount = Rs. 31360 when Rate = 12%

7 0

3 years ago