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kaheart [24]
3 years ago
5

ALGEBRA 2- If f(x)= √x-3 , which inequality can be used to find the domain of f(x)?

Mathematics
2 answers:
Fed [463]3 years ago
8 0
B, because you can't get the square root of a negative number
baherus [9]3 years ago
6 0

Answer:

Option B

Step-by-step explanation:

The given equation function is f(x) =\sqrt{x-3}

Domain of this function will be determined by (x-3) ≥ 0

because square root of negative numbers is not defined.

Option B is the answer.

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Why are and Iby 4<br>and - 1 zeroes of the polynomial p(x) <br>= 4² +3x-1?​
Serggg [28]

Answer:

- 1 = 16 + 3x - 1 \\ 3x = 16 - 1 + 1 \\  \frac{3x}{3} =  \frac{16}{3}  \\  x = 5.33

7 0
2 years ago
lily swims a 100-meter race. she swims the first half in 27.8 seconds. she swims the second half in 30.12 seconds. how long does
Luden [163]

we know that

1) Lily swims a 100-meter race

2) She swims the first half in 27.8 seconds

3) She swims the second half in 30.12 seconds

so

To find the total time to swim the whole race sum the time in the first half plus the time in second half

(27.8+30.12)=57.92\ seconds

therefore

<u>the answer is</u>

57.92\ seconds

3 0
3 years ago
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Let f and g be two functions whose second derivatives are defined. Then (f · g) '' = f · g '' + f '' · g. true or false?
Marianna [84]
I hope this helps you

8 0
2 years ago
If you run for 0.4 hours at 7 mph, how fast should you walk during the next 0.8 hours to have the average speed of 5 mph?
Fantom [35]

Answer:

4 mph

Step-by-step explanation:

The average speed of an object is given by the total distance covered by the time taken:

v=\frac{d}{t}

where

d is the total distance covered

t is the time taken

in the first part, the person runs for 0.4 hours at a speed of 7 mph, so the distance covered in the 1st part is

d_1 = v_1 t_1 = (7)(0.4)=2.8 mi

Then the distance covered in the second part is d_2, so the total distance is

d=2.8+d_2 (1)

The total time elapsed is 0.4 hours (first part) + 0.8 hours (second part), so

t=0.4+0.8=1.2 h

So we can write the average speed as

v=\frac{2.8+d_2}{1.2} (1)

We want the average speed to be 5 mph,

v = 5 mph

Therefore we can rearrange eq.(1) to find d2:

d_2 = 1.2v-2.8 = (1.2)(5)-2.8=3.2 mi

And therefore, the speed in the second part must be

v_2=\frac{d_2}{t_2}=\frac{3.2}{0.8}=4 mph

4 0
2 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPP
katen-ka-za [31]

Answer:

Sorry bro i don't know this

Step-by-step explanation:

But can u make me the Brainliest pls

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