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Marianna [84]
3 years ago
12

The function below crosses thr x-axis once. Y=3×2-8x+8

Mathematics
1 answer:
lukranit [14]3 years ago
4 0
It will be at point (5,5)
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Sever21 [200]
The answer is y=-5x :)
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A picture frame can hold a photograph that is 16 inches long and 12 inches wide.
Mila [183]

Answer:

192 inches because 16×12=192

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Six customers enter a gift shop during a 3-hour period. On average there are 0.25 customers in the gift shop and each spends 7.5
Stolb23 [73]

Answer:

6 is most directly associated with the flow rate of customers

Step-by-step explanation:

Reason:

0.25 is the number of customers in the gift shop at a given point of time is WIP inventory

7.5 is the average time spent by customer in the shop and it is the throughput time.

Flow rate = WIP inventory/Throughput time

=0.25/7.5

= 0.0333 per minute = 2 per hour or 6 per 3 hour as given in question.

6 0
3 years ago
Find the longer leg of the triangle.
Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

  • The length of the hypotenuse (the side opposite to the right angle) is given.
  • The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let \text{Opposite} denotes the length of the side opposite to the 30^{\circ} acute angle, and \text{Adjacent} be the length of the side next to this 30^{\circ} acute angle.

\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}.

Similarly,

\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}.

The longer leg in this case is the one adjacent to the 30^{\circ} acute angle. The answer will be 3.

There's a shortcut to the answer. Notice that \sin{30^{\circ}} < \cos{30^{\circ}}. The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the 30^{\circ} angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship \sin{\theta} < \cos{\theta} holds for all acute angles? (That is, 0^{\circ} < \theta?) It turns out that:

  • \sin{\theta} < \cos{\theta} if 0^{\circ} < \theta;
  • \sin{\theta} > \cos{\theta} if 45^{\circ} < \theta;
  • \sin{\theta} = \cos{\theta} if \theta = 45^{\circ}.

4 0
3 years ago
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You spin the spinner shown below once. Each sector shown has an equal area.
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Hope This Helps!!!

Hope This Helps!!!Have A Great Day!!!

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