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3 years ago

What is the surface area of a cube with faces that each have an area of 16 cm2?

2 answers:

6 0

The cube have 6 faces.
The area of the one face is equal 16 cm².

Therefore:
Surface area of the cube: S=6 × 16 cm² = 96 cm²

Pani-rosa [81]3 years ago

5 0

To find out what one side measures you will have to take the square root of the Area.

$\sqrt{16} =4$

To find out surface area of the cube you use the formula $A=6 a^{2}$ , where a = side.

Therefore,
$A=6 (4^{2})$
$A=6 (16)$
$A=96cm^{2}$

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A quadrilateral with two pairs of parallel sides is always a parallelogram

never [62]

I’m guessing this is a true or false? It is true.

5 0

3 years ago

Brad buys a jacket that is on sale for 30% off the original price.The expression p - 0.3p can be used to find the sale price of

attashe74 [19]

Answer:

$56

Step-by-step explanation:

The jacket is on sales for 30% off the original price = (0.3)

The original price (P) = $80

However, the expression "p - 0.3p" is to be used to find the sales price

The sale price = p - 0.3p

The sale price = $80 - 0.3($80)

The sale price = $80 - $24

The sale price = $56

3 0

3 years ago

Determine the domain of the following graph:

dedylja [7]

Answer:

Domain: -5, -3, -2, 1, 3

Step-by-step explanation:

Find all the points on the x-axis that line up with the line shown on the graph.

8 0

2 years ago

Suppose a production line operates with a mean filling weight of 16 ounces per container. Since over- or under-filling can be da

miss Akunina [59]

Answer:

From the question we are told that

The population mean is $\mu = 16$

The sample size is n = 30

The sample mean is $\= x = 16.32$

The population standard deviation is $\sigma = 0.8$

The level of significance is $\alpha = 0.10$

Step 1: State hypotheses:

The null hypothesis is $H_o : \mu = 16$

The alternative hypothesis is $H_a : \mu \ne 16$

Step 2: State the test statistic. Since we know the population standard deviation and the sample is large our test statistics is

$t = \frac{ \= x -\mu }{ \frac{\sigma}{ \sqrt{n} } }$

=> $t = \frac{ 16.32 -16 }{ \frac{0.8 }{ \sqrt{30} } }$

=> $t =2.191$

Generally the degree of freedom is mathematically represented as

$df = n - 1$

=> $df = 30 - 1$

=> $df =29$

Step 3: State the critical region(s):

From the student t-distribution table the critical value corresponding to $\alpha = 0.10$ is

$t = 1.311$

Generally the critical regions is mathematically represented as

$- 1.311 < T < 1.311$

Step 4: Conduct the experiment/study:

Generally the from the value obtained we see that the t value is outside the critical region so the decision is [Reject the null hypothesis ]

Step 5: Reach conclusions and state in English:

There is sufficient evidence to show that the filling weight has to be adjusted

Step 6: Calculate the p-value associated with this test. How does this the p-value support your conclusions in Step 5?

From the student t-distribution table the probability value to the right corresponding to $t =2.191$ at a degree of freedom of $df =29$ is

$P( t > 2.191) = 0.0183$

Generally the p-value is mathematically represented as

$p-value = 2 * P( t > 2.191 )$

=> $p-value = 2 * 0.0183$

=> $p-value = 0.0366$

Generally looking at the value obtained we see that $p- value < \alpha$ hence

The decision rule is

Reject the null hypothesis

Step-by-step explanation:

4 0

3 years ago

Is this equation an identity? (2x+1)^2-(x+1)^2=3(x+1)^2-1

sergey [27]

Answer:

See below, please

Step-by-step explanation:

Left side

${(2x + 1)}^{2} - {(x + 1)}^{2}$

$= (4 {x}^{2} + 4x + 1) - ( {x}^{2} + 2x + 1)$

$= (4 {x}^{2} - {x}^{2} ) + (4x - 2x) + (1 -1 )$

$= 3 {x}^{2} + 2x$

Right side

$3 \times {(x + 1)}^{2} - 1$

$= 3 \times ( {x}^{2} + 2x + 1) - 1$

$= 3 {x}^{2} + 6x + 3 - 1$

$= 3 {x}^{2} + 6x + 2$

After compared with both sides, we can make a conclusion that

This equation isn't an identity.

6 0

2 years ago