Given tan0=4/3 and sin(-4/5),finde cos 0
1 answer:
<span>x=theta
so we know that tanx = sinx/cosx
therefore is tanx = 4/3 and sinx = -4/5
we can set up an equation to find cosx
so 4/3 = (-4/5)/cosx
we can multiply x to have cosx(4/3)=-4/5
we can then divide 4/3 over so we have
cosx = (-4/5)/(4/3)
therefore, cos x = -3/5
</span>
there is the answer
i hope this help
so we know that tanx = sinx/cosx
therefore is tanx = 4/3 and sinx = -4/5
we can set up an equation to find cosx
so 4/3 = (-4/5)/cosx
we can multiply x to have cosx(4/3)=-4/5
we can then divide 4/3 over so we have
cosx = (-4/5)/(4/3)
therefore, cos x = -3/5
</span>
there is the answer
i hope this help
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2(x + 4) =
x + 4 which is the second option is the equivalent expression.
Explanation:
First, we need to calculate the value of two-fifths of x. It means 2 portions out of the five portions of x which equates to x.
Now we calculate the values of the two expresssions on the LHS.
1) 2 (two-fifths x + 2) = 2 (x + 2) =
x + 4.
2) (two-fifths x + 4) = 2(x + 4) =
x + 8.
Now we determine values of the four expressions on the RHS.
1) Two and two-fifths x + 1 = 2x + 1
2) Four-fifths x + 4 = x + 4
3) Four-fifths x + 2 = x + 2
4) Two and two-fifths x + 8 = 2x + 8.
Out of the various LHS and RHS values, the LHS value and
RHS value is the same. So option 2 is the answer.