9!/3! A.3 B.6 C.60,480 D.362,874
2 answers:
You might be interested in
Given
To find a solution for the linear equation, the first step is to write the equation in slope-intercept form:
-Pass the x-term to the right side of the equation by applying the opposite operation to both sides of the equal sign:
-Divide both sides by -2:
Once you have expressed the equation of the line in slope-intercept form, replace it with any value for x and calculate the corresponding value of y, for example, x=2
One solution for the linear equation is x=2 and y=-6, you can check the solution by replacing the values on the original equation, with both values the result should be 8:
As you can see the values are a valid solution for the linear equation.
So the solution is:
Answer:
246.3%
the complete question is found in the attached document
Step-by-step explanation:
1st step:
using 1936 data,
w1= 356% = 3.56(356/100) , H= 79 feet
specific gravity = 2.65
Sₓ= 100%= 1
initial void ratio(e₀)= (w1 x specific gravity)/Sₓ
=3.56 x 2.65/1 = 9.434
2nd step
using 1996 data
ΔH= 22ft
ΔH/H = Δe/(1 + e₀)
22/79 = Δe/(1+9.434)
0.278=Δe/10.434
Δe= 0.278 x 10.434
Δe= 2.905
Δe= e₀ - eₓ
eₓ= e₀-Δe
eₓ= 9.434 - 2.905
eₓ= 6.529
3rd step
calculating water content in 1996
eₓ =6.529, specific gravity= 2.65, Sₓ= 100%
W2 X 2.65 = 1 x 6.529
w2 = 6.529/2.65 = 2.463 = 246.3%
Answer:
40 Tickets
80 Tickets
Step-by-step explanation:
To find how many tickets it will take to break even, we use the formula:
Our variables are:
Fixed Cost = $200
Sales Price = $10
Variable Cost = $5
Let's plug in our values into the formula.
So the class needs to sell a total of 40 Tickets to break even.
Since we know that it takes 40 tickets to break even a $200 Fixed cost. To make a profit of $200, we simply multiply the number of tickets sold by 2.
Number of tickets for $200 profit = 40 x 2
Number of tickets for $200 profit = 80 Tickets.
So the class needs to sell 80 Tickets to make a $200 Profit.