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3 years ago

The amount of goods and services each dollar buys at a given point in time is called:

1 answer:

4 0

The amount of goods and services each dollar buys at a given point in time is called: Purchasing power.
The term defines the number and quality or value of goods and services that can be purchased with one unit of money.
Purchasing power loss happen when prices increase, while purchasing power gain happens when prices decrease.

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The following data pertains to activity and maintenance costs for two recent years:

Aleksandr-060686 [28]

Answer:

Y= 6000 + 0.75X

Explanation:

High and low cost technique

Using the a high and low technique, total cost can be analysed and separated into fixed and variable portion. This analysis helps in the forecast of cost and therefore important for the preparation of budget.

Variable cost of maintenance

= (Cost at high activity - Cost at low activity)/ (high activity - low activity)

VC per act. = ( $15000 - $12000)/(12,000-8000)

= $0.75 per activity

Fixed cost of maintenance

= Total cost at high activity - (VC per act × high activity)

= $15,000 - ( $0.75 × 12,000)

= $6,000

The cost formula will be:

Y= 6000 + 0.75X

Where Y = maintenance cost, X= level of activity

6 0

3 years ago

Job A3B was ordered by a customer on September 25. During the month of September, Jaycee Corporation requisitioned $1,500 of dir

Dmitriy789 [7]

Answer:

The answer is: $29,000

Explanation:

To calculate Job A3B's costs during September we must add direct materials plus 3 times direct labor:

September costs = direct materials + (direct labor x 3) = $1,500 + $9,000

September costs = $10,500

We do the same for October:

October costs: direct materials + (direct labor x 3) = $2,000 + $16,500

October costs = $18,500

The total cost for Job A3B is: $10,500 + $18,500 = $29,000

5 0

3 years ago

During 2016, Rao Co. introduced a new line of machines that carry a three-year warranty against manufacturer's defects. Based on

Over [174]

Answer:

$319,000

Explanation:

The computation of the liability is shown below:

= Total expenses in three year - actual warranty expenditure

where,

Total expenses in three years = Total sales × total percentage of sales

= $6,200,000 × 9%

= $558,000

And, the actual warranty expenditure is $239,000

Now put these values to the above formula

So, the value would equal to

= $558,000 - $239,000

= $319,000

6 0

3 years ago

Which of the following has given consumers unprecedented power to express likes and dislikes, compare prices, find the best deal

STatiana [176]

Answer:

The correct answer is letter "A": Digital technology.

Explanation:

When talking about commerce, digital technology has allowed buyers and sellers from different parts of the world find and offer goods and services without the need to physically meet. The transaction also includes all the steps and efforts necessary to deliver consumers the product at the door of their houses.

Besides, digital technology has allowed consumers to express their ideas massively based on the experience they had with the digital vendors and price so other prospective consumers have an idea of the service provided by the merchant is good or if they should look for a different seller.

8 0

3 years ago

Baker's Supply imposes a payback cutoff of 3.5 years for its international investment projects. If the company has the following

sweet-ann [11.9K]

Answer:

Both projects fall within the acceptable payback period, so, both projects can be accepted.

Explanation:

Cash payback period measures how long it takes for the amount invested in a project to be recovered from the cumulative cash flows.

Pay back period For project A:

Amount invested in the project = −$ 62,000

Amount recovered in year 1 = −$ 62,000 + 7,100 = $-54,900

Amount recovered in year 2 = $-54,900 + 9,800 = $-45,100

Amount recovered in year 3 = $-45,100 + 28,700 = $-16,400

Amount recovered in year 4 = $-16,400 + 45,900 = $29,500

The amount is recovered In 3 years + 16400 / 45900 = 3.36 years

Cash payback period for project B:

Amount invested in the project = −$ 26,000

Amount recovered in year 1 = −$ 26,000 + 15,600 = $-10,400

Amount recovered in year 2 = $-10,400 + 8,400 = $-2000

Amount recovered in year 3 = $-2000 + 1,900 = $-100

Amount recovered in year 4 = $-100 + 1,100 = $1000

The amount invested is recovered In 3 years + 100/1,100 = 3.09 years.

Both projects fall within the acceptable payback period, so, both projects can be accepted.

I hope my answer helps you

7 0

3 years ago