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Answer:
4.10
5. 16
6. B.
7. B.
8. A.
Step-by-step explanation:
I believe this would be it. Hoped this helped!
Answer:
Polygon q’s area is one fourth of polygon p’s area
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z-----> the scale factor
x-----> polygon q’s area
y-----> polygon p’s area
so
In this problem we have
substitute
therefore
Polygon q’s area is one fourth of polygon p’s area
1. Let the first integer be represented by: 2k
the second integer by: 2(k+1)
the third integer by: 2(k+2)
and the fourth by: 2(k+3)
Then, 2k + 2(k+2) = 2(k+3) - 6
2k + 2k + 4 = 2k + 6 - 6
4k + 4 = 2k
4 = -2k
-2 = k
Answer: -4, -2, 0, 2
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2. Let the first integer be represented by: 2k+1
the second integer by: 2k+3
the third integer by: 2k+5
and the fourth by: 2k+7
Then, 2k+7 = (2k+1) + (2k+3) + (2k+5) + 2
2k + 7 = 6k + 11
-4 = 4k
-1 = k
Answer: -1, 1, 3, 5
Answer:
96
Step-by-step explanation:
6a²
Put a as 4.
6(4)²
Solve for power first.
6(16)
Multiply both terms.
= 96
