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Vika [28.1K]
3 years ago
10

What quantity of a 50% acid solution must be mixed with a 20% solution to produce 600 mL of a 45% solution?

Mathematics
1 answer:
Naddika [18.5K]3 years ago
4 0

Answer:

400 mL

Step-by-step explanation:

0.50x + 0.20(600-x) = 0.40*600

50x + 20*600 - 20x = 40*600

30x = 20*600

x = 20*20

x = 400 mL

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Tomas reparte 9 kg de mandarinas en mallas de tres cuartos de kilo cada una . ¿Cuantas mallas obtiene?
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8 0
3 years ago
6.81 is what percent of 45.5
frosja888 [35]

To get the solution, we are looking for, we need to point out what we know.

1. We assume, that the number 45.5 is 100% - because it's the output value of the task.

2. We assume, that x is the value we are looking for.

3. If 45.5 is 100%, so we can write it down as 45.5=100%.

4. We know, that x is 6.81% of the output value, so we can write it down as x=6.81%.

5. Now we have two simple equations:

1) 45.5=100%

2) x=6.81%

where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:

45.5/x=100%/6.81%

6. Now we just have to solve the simple equation, and we will get the solution we are looking for.


7. Solution for what is 6.81% of 45.5


45.5/x=100/6.81

(45.5/x)*x=(100/6.81)*x       - we multiply both sides of the equation by x

45.5=14.684287812041*x       - we divide both sides of the equation by (14.684287812041) to get x

45.5/14.684287812041=x

3.09855=x

x=3.09855

now we have:

6.81% of 45.5=3.09855

Hope this helps!

4 0
3 years ago
Read 2 more answers
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