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3 years ago

the end points of a diameter of a circle are A(3,1) and B(8,13). Find the area of the circle in terms of X

Mathematics

2 answers:

katrin2010 [14]3 years ago

7 0

Answer:

I think it's 4.52. Only if that's one of the options I guess. Good luck!

Volgvan3 years ago

6 0

Answer:

(25/4)∏ or (6 1/4)∏

Step-by-step explanation:

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Equation for the points (3,8) (2,6) on slope

Irina18 [472]

$\frac{8-6}{3-2} = \frac{2}{1}=4$

The slope is 2

y=2x + b

Plug in a point to solve for b
8 = 2(3) + b

8 = 6 + b
b = 2

The equation is y = 2x + 2

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3 years ago

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What is the measure of angle A in the triangle below?

laiz [17]

The answer is 30.
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3 years ago

The lateral area of a right cylinder which has a base diameter of 12 cm and a height of 8 cm is?

garik1379 [7]

Answer:

$A = 301.59\ cm^2$ or $A=96\pi\ cm^2$

Step-by-step explanation:

The lateral area of a cylinder is calculated by the following formula

$A = 2\pi r * h.$

Where r is the radius of the right cylinder and h is the height

In this case we know that the diameter d of the cylinder is

$d=2r\\\\r=\frac{d}{2}\\\\r=\frac{12}{2}\\\\r=6\ cm$

$h=8\ cm$

Therefore the lateral area is:

$A = 2\pi*6 * 8.$

$A = 96\pi$

$A = 301.59\ cm^2$

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3 years ago

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1.The triangle ABC has the vertices A(-9, -3) B(1. -3), C(-9, 6)

Nina [5.8K]

Answer:

1. A

2. D

3. D

4. C

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3 0

3 years ago

$13,957 is invested, part at 7% and the rest at 6%. If the interest earned from the amount invested at 7% exceeds the interest e

ch4aika [34]

Answer:

The Amount invested at 7% interest is $12,855

The Amount invested at 6% interest = $1,102

Step-by-step explanation:

Given as :

The Total money invested = $13,957

Let The money invested at 7% = $p_1$ = $A

And The money invested at 6% = $p_2$ = $13957 - $A

Let The interest earn at 7% = $I_1$

And The interest earn at 6% = $I_2$

$I_1$ - $I_2$ = $833.73

Let The time period = 1 year

Now,<u> From Simple Interest method</u>

Simple Interest = $\dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}$

Or, $I_1$ = $\dfrac{\textrm p_1\times \textrm 7\times \textrm 1}{100}$

Or, $I_1$ = $\dfrac{\textrm A\times \textrm 7\times \textrm 1}{100}$

And

$I_2$ = $\dfrac{\textrm p_2\times \textrm 6\times \textrm 1}{100}$

Or, $I_2$ = $\dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100}$

∵ $I_1$ - $I_2$ = $833.73

So, $\dfrac{\textrm A\times \textrm 7\times \textrm 1}{100}$ - $\dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100}$ = $833.73

Or, 7 A - 6 (13,957 - A) = $833.73 × 100

Or, 7 A - $83,742 + 6 A = $83373

Or, 13 A = $83373 + $83742

Or, 13 A = $167,115

∴ A = $\dfrac{167115}{13}$

i.e A = $12,855

So, The Amount invested at 7% interest = A = $12,855

And The Amount invested at 6% interest = ($13,957 - A) = $13,957 - $12,855

I.e The Amount invested at 6% interest = $1,102

Hence,The Amount invested at 7% interest is $12,855

And The Amount invested at 6% interest = $1,102 . Answer

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3 years ago