Parameterize this surface (call it
) by

with
and
. Take the normal vector to
to be

Then the area of
is



Answer:
29.6 feet
Step-by-step explanation:
Answer:
the angle abc is 180 degrees
All you have to do is plug in 4 where n is
In other words n = 4
So...
F(n) = 5^n
F(4) = 5^4 or (5 x 5 x 5 x 5)
F(4) = 625
Answer:
class a- 10
class b- 15
Step-by-step explanation: