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harkovskaia [24]
3 years ago
6

a math book is 1 and 1/2 inches thick. How many math books will fit on a shelf that is 2 feet long?

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
6 0
16 because 2 feet is 24 inches and 24 divided by 1.5 is 16
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the captain of a boat knows that the lighthouse on the coast is 200 feet tall. he measures the angle of elevation to the top of
krek1111 [17]

Answer:

The boat is 5727.25ft far from the coast

Step-by-step explanation:

Refer the figure given.

We need to find how far is the boat from the coast = AB

Angle of elevation = 2°

The lighthouse on the coast is 200 feet tall, AC = 200 ft

We have

           tan2=\frac{AC}{AB}=\frac{200}{AB}\\\\AB=\frac{200}{tan2}=5727.25ft

The boat is 5727.25ft far from the coast

7 0
3 years ago
A magician is performing for an audience of 32 men and 20 women. He selects a volunteer from the audience, has the volunteer sta
statuscvo [17]
32+20=52 so there are 52 people in all. 
32/52  people are men.
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we multiply 32/52 with 31/51 to get 248/663. simply turn this fraction into a percent by multiplying the quotient by 100 and rounding it to the nearest tenth to get 37.4%
6 0
3 years ago
Find the value of x in the triangle
SVEN [57.7K]

Answer:

x = 112

Step-by-step explanation:

180 - 41 - 27 = 112

All the angles of a triangle need to add up to 180 degrees.

3 0
3 years ago
If you got 11/20 on your exam, how much would it be on /100​
Serga [27]

Answer:

55/100

Step-by-step explanation:

Multiply 20 by 5 to get 100 so you multiply 11 by 5 to get 55

4 0
3 years ago
The radius of a right circular cylinder is increasing at the rate of 3 ft/sec, while the height is decreasing at the rate of 6 f
goblinko [34]

Answer:

\frac{dV}{dt}=-450\pi ft^3/sec

Step-by-step explanation:

Let's assume

radius of cylinder as 'r'

height of cylinder as 'h'

so, we have

\frac{dr}{dt} =3ft/sec

\frac{dh}{dt} =-6ft/sec

r=15ft

h=10ft

now, we can use volume of cylinder formula

V=\pi r^2h

we can find derivative with respect to t

\frac{dV}{dt}=2\pi r h\times\frac{dr}{dt} +\pi r^2\times \frac{dh}{dt}

now, we can plug values

\frac{dV}{dt}=2\pi (15)(10)\times3 +\pi (15)^2\times -6

now, we can simplify it

\frac{dV}{dt}=-450\pi ft^3/sec

6 0
3 years ago
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