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3 years ago

15

Write 4.625 as a mixed number in simplest form

1 answer:

Zarrin [17]3 years ago

4 0

4 625/1,000 to 4 25/40 to 4 5/8

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Factorising quadratics <br><br> All questions please to be completed. I’m stuck.

Alex777 [14]

Answer:

1. (x +1)(x - 1)

2. (x+5)(x-5)

3. (x+12)(x-12)

4. (x+14)(x-14)

5. (x+5)(x-7)

Step-by-step explanation:

The first 4 expressions can be factored with the difference of squares type of factoring.

For #5, the odd one out is (x+5)(x-7) because it isn't a factor of any of the standard form equations, while the others are

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3 years ago

Jessica took out a Stafford loan worth $7,175 at the beginning of her six-year college career. The loan has a duration

Andrew [12]

Answer:

c . $37.6756⅞8999999567824dg

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3 years ago

Read 2 more answers

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

3 years ago

An urn contains a very large number of marbles of four diﬀerent colors: red, orange, yellow, and green. A sample of 12 marbles d

Umnica [9.8K]

Answer:

We can reject the hypothesis at the 0.05 signiﬁcance level.

Step-by-step explanation:

given that an urn contains a very large number of marbles of four diﬀerent colors: red, orange, yellow, and green. A sample of 12 marbles drawn at random from the urn revealed 2 red, 5 orange, 4 yellow, and 1 green marble.

H0: All colours are equally likely

Ha: atleast two colours are not equally likely

(Two tailed chi square test at 5% significance level)

color Red Orange Yellow Green total

Observed O 2 5 4 1 12

Expected E 3 3 3 3 12

(O-E)^2/E 0.3333 5.3333 0.3333 5.3333 11.3333

chi square = 11.3333

df =3

p value = 0.010055

Since p < 0.05 we reject H0

We can reject the hypothesis at the 0.05 signiﬁcance level.

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3 years ago

Which of the following is the standard form for y+4= 1.5(x-4)

MatroZZZ [7]

Answer: y= 1.5x -2 we find this by solving

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3 years ago