Answer:
no you shouldn't get grounded for getting water that was d u m b to get grounded for that
Step-by-step explanation:
Step-by-step explanation:
Perpendicular slopes must be opposite reciprocals of each other: m1 * m2 = –1
4x+ y= 3
y= -4x + 3
slope = -4
the new slope = 1/4
the equation formula y= mx+b
m = new slope
y = (x/4) + b
From the point given (4,-3)
y = -3. x = 4
-3 = 1 + b
b = -4
the equation =

Answer:
B
Step-by-step explanation:
Since the triangle is right use the sine/ tangent ratios to solve for x and y
note sin60° =
and tan60° = 
sin60° =
= 
ysin60° = 3
y ×
= 3
multiply both sides by 2 and divide by 
y v= 6
= 6
tan60° =
= 
xtan60° = 3
x ×
= 3
divide both sides by 
x = 3
= 3
The domain in a relation y(x) is the set of values for which the relation is defined (the values on x, where y is defined)
In this relation the values wich the relation is defined is: the coordinates of x where there are a point:
Domain: -1, 0, 3
The range in a relation y(x) is the set of all the values that y(x) takes (the values of y)
In this relation the values that takes y(x) are the coordinates of y where there are a point:
Range: -3, -1, 0