Please can you answer question b

Mathematics

1 answer:

alexira [117]2 years ago

3 0

198 + (199*3) + (200*2) +(201*5) + (202*2) = 2604

frequency = 1 + 3 +2 + 5 + 2 = 13

201 = (2604 + x )/14
multiply both sides by 14
x = 201*14 = 2604 +x

x = 2814 = 2604 +x

subtract 2604 from both sides:

x = 2814 - 2604
x = 210 cm

height of new player = 210 cm

You might be interested in

A number changed to 12.6 after it was rounded. To what place was the number rounded? Explain how you know.

Anton [14]

If 12.6 was rounded, that means that it was rounded to the tenths place.
You know this because the number has one decimal place, so that must be what it was rounded to.

4 0

3 years ago

What are the zeros of the function f(x)= 2x^2-4x-6

jolli1 [7]

The root are x=3 and x=-1

youre welcome :)

5 0

3 years ago

Nolan's Term Grades

Anvisha [2.4K]

Ex. 85+91= 176
176 divided by 2 = 88
Therefore the minimum score he can get is a 91

3 0

3 years ago

look at the figure shown below which step should be used to prove that point a is equidistant from points c and b

JulijaS [17]

D
is certainly wrong. You could extend the length of AD as far as you want and the two triangles (ABD and ACD) would still be congruent.

C
is wrong as well. The triangles might be similar, but they are more. They are congruent.

B
You don't have to prove that. It is given on the way the diagram is marked.

A
A is your answer. The two triangles are congruent by SAS

3 0

2 years ago

Given that <img src="https://tex.z-dn.net/?f=I_0%20%3D%2010%5E-12" id="TexFormula1" title="I_0 = 10^-12" alt="I_0 = 10^-12" alig

Alex Ar [27]

The intensity of sound which the decibel level of the sound measures 156 is 3.981 × 10³ W/m²

Decibel level, dB = 10log₁₀(I/I₀) where dB = decibel level = 156, I = intensity at 156 dB and I₀ = 10⁻¹² W/m².

Since we require I, making I subject of the formula, we have

dB/10 = log₁₀(I/I₀)

$\frac{I}{I_{0} } = 10^{\frac{dB}{10} } \\I = I_{0} 10^{\frac{dB}{10} }$

Substituting the values of the variables into the equation, we have

$I = I_{0} 10^{\frac{dB}{10} }\\I = 10^{-12} 10^{\frac{156}{10} }\\I = 10^{-12} 10^{15.6}\\I = 10^{15.6-12} \\I = 10^{3.6} W/m^{2}$

I = 3981.072W/m²

I = 3.981 × 10³ W/m²

So, the intensity of sound which the decibel level of the sound measures 156 is 3.981 × 10³ W/m²

Learn more about intensity of sound here:

brainly.com/question/4431819

3 0

2 years ago