A book with a mass of 1.5 kg rests on the edge of a desk 0.75 m above the

A 120 V fish-tank heater is rated at 130W. Calculate (a) the current through the heater when it is operating, and (b) its resist

7nadin3 [17]

Explanation:

The power P dissipated by a heater is defined as

$P = VI$

where V is the voltage and I is the current.

a) The current running through a 130-W heater is

$I = \dfrac{P}{V} = \dfrac{130\:\text{W}}{120\:\text{V}} = 1.08\:\text{A}$

b) The resistance R of the heater is

$P = VI = (IR)I = I^2R$

where $V= IR$ is our familiar Ohm's Law.

$\Rightarrow R = \dfrac{P}{I^2} = \dfrac{130\:\text{W}}{(1.08\:\text{A})^2}$

$R = 110.8\:Ω$

8 0

3 years ago

A liquid with a density of 900kg/m 3 is stored in a pressurized, closed storage tank. The tank is cylindrical with a 10m diamete

Orlov [11]

Answer:

18.62 m/s

Explanation:

Given that:

A liquid with a density of 900 kg/m 3 is stored in a pressurized, closed storage tank.

Diameter of the tank = 10 m

The absolute pressure in the tank above the liquid is 200 kPa = 200, 000 Pa

At pressure of 200 kPa ; the final velocity = 0

Atmospheric pressure at 5cm = 101325 Pa

We are to calculate the initial velocity of a fluid jet when a 5cm diameter orifice is opened at point A?

By using Bernoulli's theorem between the shaded portion in the diagram;

we have:

$Pa \ + \ \frac{1}{2} \ \delta \ v^2_1 \ + \ \delta gy_1 = P + \delta gy_2$

$\frac{1}{2} \ \delta \ v^2_1 \ = P + \delta gy_2 - \ \delta gy_1 - Pa$

$\frac{1}{2} \ \delta \ v^2_1 \ = \delta g(y_2 -y_1 )+ ( P - Pa )$

$v_1 \ = \sqrt{ \frac {2 \ \delta g(y_2 -y_1 )+ 2 ( P - Pa )}{\delta}}$

where;

Pa = atmospheric pressure = 101325 Pa

$\delta$ = density of liquid = 900 kg/m³

$v_1$ = initial velocity = ???

g = 9.8 m/s²

$y_1$ = height of the hole from the buttom

$y_2$ = height of the liquid surface from the button

$v_1 \ = \sqrt{ \frac {2*900*9.8(7 - 0.5 )+ 2 ( 200,000 - 101325 )}{900}}$

$v_1 = 18.62 \ m/s$

Thus, the initial velocity of the fluid jet = 18.62 m/s

3 0

3 years ago

Equation: S=D]

Ahat [919]

The speed of car is 106.67 miles per hour

To solve problems involving speed and distance we are required to first find speed or distance travelled in an hourly timeframe

It is given that car takes 4 hours to cover the distance at a speed of 40 miles per hour

Therefore, total distance travelled by the car= speed x time

= 40 miles per hour x 4 hour

=160 miles

We are required to find the speed of the car if the distance is to be covered in 1.5 hours

We are required to find the speed by the formula speed= Distance/time

distance= 160 miles time = 1.5 hour

speed= 160/1.5=106.666=106.67 miles per hour

Hence the speed is 106.67 miles per hour

For further reference:

brainly.com/question/10930186?referrer=searchResults

#SPJ9

7 0

2 years ago

Need help... 44 points!!!!

vladimir1956 [14]

As per conditions described here we know that all force arrow are not of equal length

So all forces are not same in magnitude

Here applied force on right direction is more in magnitude then the friction force on left

So it will have net unbalanced force towards right due to which it will move towards right direction or in the direction of net unbalanced force

While in the upward and downward direction the forces are balanced and hence the box will not move in that direction

So normal force will be balanced by gravitational force

So here answer will be

The forces acting on the box are UNBALANCED .

The box will move to the RIGHT .

7 0

4 years ago

Read 2 more answers

Natalia lifts a bag of groceries 0.50 m by exerting a force of 36 N. How much work did she do on the bag?

Kruka [31]

<h3>Answer;</h3>

18 Joules

<h3>Explanation;</h3>

Work is the measures the transfer of energy when an object moves over a given distance.

Work is therefore given by; Force × distance

Force =36 Newtons

Distance = 0.5 meters

Hence; work = 36 N × 0.5 N

 = 18 Joules 

5 0

3 years ago

Read 2 more answers