Its 11 cause I’m built different
Vertex: (-5,-2); parabola opens up;
General form of the equation for a vertical parabola opening up is:
y-k = a(x-h)^2; knowing that the vertex is at (-5,-2), we can write:
y+2 = a(x+5)^2. We need to find the value of the coefficient a.
From the graph we see that y is 10 when x is approx. -1 3/4 (or -7/4).
subst. these values into y+2 = a(x+5)^2, we get:
10 + 2 = a(-7/4 + 5)^2, or 12 = a(13/4)^2, or 1 = a(169/16).
Solving for a: a = 16/169 = 0.09, or approx 16/160, or 1/10. Unfortunately, this is not close to any of the four answer choices.
I thought it best to try again, and fortunately my second try was correct:
10+2 = a(13/4)^2, or (169/16)a. Thus, 12 = a(169/16)
12
Solving for a: a = ------------- = 1.14. The answer choice closest to this is 1.
169/16
Answer A is correct.
x=76
y=4
I think that answer should be right. Since it is isosceles the base angles will be the same and the top angle is an angle bisector which means that the angle split on top has even splits. Since no other side lengths- or any lengths at that matter- are give, it is safe to assume that y=4.
2x - 9x = 14 (Careful next time you accidentally added an "equal" next to the 2)
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Simplify
2x-9x=<span>14
</span><span>2x+-9x</span>=<span>14
</span>--------------------------------------------
Combine the like-terms
<span>(<span>2x+-9x</span>)</span>=<span>14
</span><span><span>-7x</span></span>=<span>14
</span>--------------------------------------------------
Now divide -7 to each side
-7x ÷ -7 = 14 ÷ -7
x = -2
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x = -2 is your answer