LaTeX: \frac{27.50\:gallons}{5\:buckets}

How do you calculate average time from a data set? These are the times: 2.22s, 2.14s, and 2.10s.

You would add them all and then decide them by how many numbers there are witch would be 3.

2.22. 3/6.46 =2.1533
2.14.
+2.10
———
6.46

6 0

3 years ago

Least common denominator again please lol. Sorry I keep asking so many questions, but hey, I guess it means you guys get more po

Olenka [21]

Answer:

hope it's help u

Step-by-step explanation:

$the \: lcm \: of \: 2 \: and \: 9 \: is \: 18.so \: the \: lcd \: is \: 18 \\ \frac{11}{2} = \frac{11 \times 9}{2 \times 9} = \frac{99}{18 } \\ \frac{1}{9} = \frac{ 1\times 2 }{9 \times 2} = \frac{2}{18} \\ \frac{99}{18} > \frac{2}{18}$

8 0

2 years ago

Plzzzzzzzz! A suitcase lock has a code 4 symbols long. The symbols on the lock are a star, a square, a circle, a triangle, a lin

34kurt

Answer:

$\dfrac{1}{30}$

Step-by-step explanation:

6 symbols and 4-symbol code so number of combinations wich doesn't contain the same symbol twice would be:

6•5•4•3 = 360

If code starts with a star followed by triangle that means only one posibility for first two symbols and code doesn't containing the same symbol twice means that left 4 symbols for next two.

So number of combinations of code starting with a star followed by triangle and doesn't containing the same symbol twice will be:

1•1•4•3 = 12

The probability that a randomly chosen code starts with a star followed by triangle and doesn't contain the same symbol twice:

$\dfrac{1\cdot1\cdot4\cdot3}{6\cdot5\cdot4\cdot3}=\dfrac{1\cdot1}{6\cdot5}=\dfrac{1}{30}$