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3 years ago

A company has 3 positions(President, VP, manager) to fill. If there are 15 candidates,

Mathematics

1 answer:

Vladimir [108]3 years ago

6 0

Answer: 455 possible outcomes

Step-by-step explanation:

If there are 3 positions and 15 candidates, you multiply 15 by 14, then by 13 to get the number of possible outcomes times 6.

This is because once a candidate gets a position, there will be 1 less candidate without a position each time.

15 * 14 * 13 = 2,730

Now, since there are only 3 positions, the first position has 3 possible ways, the second position has 2 possible ways, and the third position has 1 possible way.

3 * 2 * 1 = 6

2,730 / 6 = 455

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Suppose c was a total membership cost for m the two equations that model c are c=30m+50 an c=20m+100

Maksim231197 [3]

Answer:

5 months

Step-by-step explanation:

Given

$c = 30m + 50$

$c = 20m + 100$

Required [Missing from the question]

At what month will the cost be equal

To do this, we equate both expressions

$c = c$

This gives:

$30m + 50 = 20m + 100$

Collect like terms

$30m - 20m = 100 - 50$

$10m = 50\\$

Solve for m

$m = \frac{50}{10}$

$m = 5$

8 0

3 years ago

I NEED THIS ASAP! ILL GIVE YOU BRAINLIST!

Artist 52 [7]

I believe $30 but i am not completely sure :)

5 0

3 years ago

What is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4, 9)?

Brums [2.3K]

Answer:

The area of a rectangle is 42 units ².

Step-by-step explanation:

As the diagram is given below.

Distance Formula

$Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

As the rectangle with vertices at A (4, 3), B(11, 3),C (11, 9), and D (4, 9).

Take A (4, 3) to B(11, 3)

$AB = \sqrt{(11-4)^{2}+(3-3)^{2}}$

$AB = \sqrt{(7)^{2}+(0)^{2}}$

$AB = \sqrt{49}$

$\sqrt{49} =7$

AB = 7 units

As take B(11, 3) to C (11, 9).

$BC = \sqrt{(11-11)^{2}+(9-3)^{2}}$

$BC = \sqrt{(0)^{2}+(6)^{2}}$

$BC = \sqrt{36}$

$\sqrt{36} =6$

BC = 6 units

As take C (11, 9) toD (4, 9).

$CD = \sqrt{(4-11)^{2}+(9- 9)^{2}}$

$CD = \sqrt{(7)^{2}+(0)^{2}}$

$CD = \sqrt{49}$

$\sqrt{49} =7$

CD = 7 units

As take D (4, 9) to A (4, 3)

$DA = \sqrt{(4-4)^{2}+(3-9)^{2}}$

$DA = \sqrt{(0)^{2}+(-6)^{2}}$

$DA = \sqrt{36}$

$\sqrt{36} =6$

DA = 6 units

Thus

AB = DC= 7 units

AD = BC = 6 units

Formula

Area of rectangle = Length × Breadth

Length = 7 units

Breadth = 6 units

Put value in the above

Area of rectangle = 7 × 6

= 42 units ²

Therefore the area of a rectangle is 42 units ².

6 0

3 years ago

Read 2 more answers

A carton has a length of fraction 2 and 2 over 3 feet, width of fraction 1 and 1 over 3 feet, and height of fraction 1 and 1 ove

astraxan [27]

Writing this problem in symbols instead of in words greatly simplifies it:

(2 2/3) * (1 1/5) * (1 1/2)

Write each quantity (inside each set of parentheses) as an improper fraction:

(8/3) * (6/5) * (3/2)

Now multiply the numerators thru: 8*6*3 / 3*5*2

Notice that we can reduce this by dividing the 8 by the 2 and dividing the 6 by the 3: 4*3*3 36
---------- = -----------
5 5

7 0

3 years ago

Use RACE strategy to solve the problem “Class Picnic”:

Ber [7]

Answer:

I thank that Jordan will buy 5 packs of hamburgers and he would buy 3 bags of hamburger buns. And each student can have 1 each.

Step-by-step explanation:

sorry if its wong

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3 years ago