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3 years ago

How many ways can you write one whole as a fraction

Mathematics

2 answers:

Kryger [21]3 years ago

8 0

Answer:

infinite

Step-by-step explanation:

you could say 1/1 or 4/4 or 146798245/146798245

any number over itself is a whole

Does that answer it? I feel like I'm missing something

lbvjy [14]3 years ago

4 0

Answer:

Any

Step-by-step explanation:

You can write one whole by making the numerator and denominator the same number. Examples: 2/2 3/3 4/4 5/5 6/6 7/7 8/8 9/9 10/10 100/100 20/20

You might be interested in

A conical container can hold 120π cubic centimeters of water. The diameter of the base of the container is 12 centimeters.

nignag [31]

Answer:

A. 10cm

B. 8 times

Step-by-step explanation:

The question is on volume of a conical container

Volume of a cone= $\pi r^{2} h/3$

where r is the radius of base and h is the height of the cone

Given diameter= 12 cm, thus radius r=12/2 =6 cm

$v=\pi r^2h/3 \\120\pi =\pi *6*6*h/3\\120\pi =12\pi h\\10=h$

h=10 cm

If height and diameter were doubled

New height = 2×10 =20 cm

New diameter = 2×12 = 24, r=12 cm

volume = $v=\pi r^2h/3\\v=\pi *12*12*20/3\\v=960\pi$

To find the number of times we divide new volume with the old volume

$N= 960\pi /120\pi \\\\N= 8$

8 0

3 years ago

Read 2 more answers

HELP PLS I DONT KNOW THIS ONE

inessss [21]

Answer:

-------------

(x+2)(x-4)

Step-by-step explanation:

x+4 x+3

------------- * --------------

x^2+5x+6 x^2 -16

Factor

x+4 x+3

------------- * --------------

(x+3)(x+2) (x+4)(x-4)

Cancel like terms

1 1

------------- * --------------

(1)(x+2) (1)(x-4)

------------- x cannot equal -3, -4, -2, 4

(x+2)(x-4)

5 0

3 years ago

Which function is the same as y = 3 cosine (2 (x startfraction pi over 2 endfraction)) minus 2? y = 3 sine (2 (x startfraction p

kirza4 [7]

The function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

<h3>How to convert sine of an angle to some angle of cosine?</h3>

We can use the fact that:

$\sin(\theta) = \cos(\pi/2 - \theta)\\\sin(\theta + \pi/2) = -\cos(\theta)\\\cos(\theta + \pi/2) = \sin(\theta)$

to convert the sine to cosine.

<h3>Which trigonometric functions are positive in which quadrant?</h3>

In first quadrant (0 < θ < π/2), all six trigonometric functions are positive.
In second quadrant(π/2 < θ < π), only sin and cosec are positive.
In the third quadrant (π < θ < 3π/2), only tangent and cotangent are positive.
In fourth (3π/2 < θ < 2π = 0), only cos and sec are positive.

(this all positive negative refers to the fact that if you use given angle as input to these functions, then what sign will these functions will evaluate based on in which quadrant does the given angle lies.)

Here, the given function is:

$y= 3\cos(2(x + \pi/2)) - 2$

The options are:

$y= 3\sin(2(x + \pi/4)) - 2$
$y= -3\sin(2(x + \pi/4)) - 2$
$y= 3\cos(2(x + \pi/4)) - 2$
$y= -3\cos(2(x + \pi/2)) - 2$

Checking all the options one by one:

Option 1: $y= 3\sin(2(x + \pi/4)) - 2$

$y= 3\sin(2(x + \pi/4)) - 2\\y= 3\sin (2x + \pi/2) -2\\y = -3\cos(2x) -2\\y = 3\cos(2x + \pi) -2\\y = 3\cos(2(x+ \pi/2)) -2$

(the last second step was the use of the fact that cos flips its sign after pi radian increment in its input)
Thus, this option is same as the given function.

Option 2: $y= -3\sin(2(x + \pi/4)) - 2$

This option if would be true, then from option 1 and this option, we'd get:
$-3\sin(2(x + \pi/4)) - 2= -3\sin(2(x + \pi/4)) - 2\\2(3\sin(2(x + \pi/4))) = 0\\\sin(2(x + \pi/4) = 0$

which isn't true for all values of x.

Thus, this option is not same as the given function.

Option 3: $y= 3\cos(2(x + \pi/4)) - 2$

The given function is $y= 3\cos(2(x + \pi/2)) - 2 = 3\cos(2x + \pi) -2 = -3\cos(2x) -2$

This option's function simplifies as:

$y= 3\cos(2(x + \pi/4)) - 2 = 3\cos(2x + \pi/2) -2 = -3\sin(2x) - 2$

Thus, this option isn't true since $\sin(2x) \neq \cos(2x)$ always (they are equal for some values of x but not for all).

Option 4: $y= -3\cos(2(x + \pi/2)) - 2$

The given function simplifies to: $y= 3\cos(2(x + \pi/2)) - 2 = 3\cos(2x + \pi) -2 = -3\cos(2x) -2$

The given option simplifies to:

$y= -3\cos(2(x + \pi/2)) - 2 = -3\cos(2x + \pi ) -2\\y = 3\cos(2x) -2$

Thus, this function is not same as the given function.

Thus, the function which is same as the function y = 3cos(2(x +π/2)) -2 is: Option A: y= 3sin(2(x + π/4)) - 2

Learn more about sine to cosine conversion here:

brainly.com/question/1421592

4 0

2 years ago

Read 2 more answers

Can someone please help me I posted this multiple times but no one answers pls help me quick

mario62 [17]

You would have to make 465=1550-7 1/2 x and find x
Subtract 1550 from both sides
-1085=-7 1/2x
Divide -7 1/2 on both sides
And the answer is 144 2/3
Sorry about ur bad luck

6 0

2 years ago

3 less than c in numbers

Ira Lisetskai [31]

Answer:

Step-by-step explanation:

3<3

7 0

3 years ago