X^3+7x^2-36x 3 +7x 2 −36x, cubed, plus, 7, x, squared, minus, 36 The polynomial above has zeros at -6−6minus, 6 and 222. If the
remaining zero is zzz, then what is the value of -z−zminus, z?
1 answer:
Answer:
Step-by-step explanation:
Equation:
x^3 + 7x^2 - 36
Given that:
x1 = -6
x2 = 2
x3 = z
Let the zeros be,
x + 6, x - 2
Multiplying both of these factors ,
(x + 6) × (x - 2)
x^2 + 6x - 2x - 12
= x^2 + 4x - 12
Dividing the polynomial, x^3 + 7x^2 - 36 with the above quadratic equation,
We get:
x^3 + 7x^2 - 36 ÷ x^2 + 4x - 12
= x + 3
z; x + 3 = 0
x = -3
z = -3
-z = 3
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Answer:
Option B) 9.1
Step-by-step explanation:
We are given the following in the question:
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Standard deviation = 63.7
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Formula:
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Option B) 9.1