What grade is this? can you maybe break it down
Answer:
24
Step-by-step explanation:
Answer:
6a) 1
6b) 11
7a) 4
7b) 10
8a) 6
8b) 14
9a) 11
9b) 13
Step-by-step explanation:
In order to make a triangle, we need to follow this property:
a <= b + c
(Known as "triangle inequality")
Where 'a' is the bigger side and 'b' and 'c' are the other two sides.
So, using this property, we can solve the following problems:
6a) Maximum side will be 6:
6 <= 5 + c
c = 1
6b) Minimum sides will be 5 and 6:
a <= 5 + 6
a = 11
7a) Maximum side will be 7:
7 <= 3 + c
c = 4
7b) Minimum sides will be 3 and 7:
a <= 3 + 7
a = 10
8a) Maximum side will be 10:
10 <= 4 + c
c = 6
8b) Minimum sides will be 4 and 10:
a <= 4 + 10
a = 14
9a) Maximum side will be 12:
12 <= 1 + c
c = 11
9b) Minimum sides will be 1 and 12:
a <= 1 + 12
a = 13
Answer:

Step-by-step explanation:
see the attached figure with letters to better understand the problem
step 1
Find the measure of arc BC
we know that
----> by complete circle
substitute the given values



step 2
Find the measure of angle 2
we know that
The inscribed angle is half that of the arc it comprises.
so
![m\angle 2=\frac{1}{2}[arc\ BC]](https://tex.z-dn.net/?f=m%5Cangle%202%3D%5Cfrac%7B1%7D%7B2%7D%5Barc%5C%20BC%5D)
substitute
![m\angle 2=\frac{1}{2}[116^o]=58^o](https://tex.z-dn.net/?f=m%5Cangle%202%3D%5Cfrac%7B1%7D%7B2%7D%5B116%5Eo%5D%3D58%5Eo)