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Leviafan [203]
3 years ago
12

Question in attachment answer with work no spam

Mathematics
1 answer:
Anastaziya [24]3 years ago
7 0
<span>The derivative of a function at a point gives the slope of the line tangent to the function's graph at that point. 

</span>Therefore, f'(2)  gives the slope of the tangent line to the graph of f where  x=2 , which is the point (2,3). 

We know this line passes through (2,3) , and we are also given that it passes through (7,6). <span>This should be enough to find the slope of that line. 

</span>\text{Slope} =  \dfrac{\text{change in y}}{\text{change in x}} 

\dfrac{6-3}{7-2} 

=  \dfrac{3}{5} 

In conclusion, f'(2)=\dfrac{3}{5}
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Here slope is -2
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3 years ago
Camryn earns $198.60 per week. She works 15 hours each week. How much does Camryn earn per hour? P.S this is a unit rate questio
Musya8 [376]
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4 0
3 years ago
Choose the solution(s) of the following system of equations x2 + y2 = 6 x2 – y = 6
ElenaW [278]
<h2>Answer</h2>

x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1

Or as ordered pairs: (\sqrt{6} ,0),(-\sqrt{6} ,0),(\sqrt{5} ,-1),(-\sqrt{5} ,-1)

<h2>Explanation</h2>

Lets solve our system of equations  step by step

x^2+y^2=6 equation (1)

x^2-y=6 equation (2)

1. Solve for x^2 in equation (2)

x^2-y=6

x^2=6+y equation (3)

2. Replace equation (3) in equation (1) and solve for y

x^2+y^2=6

6+y+y^2=6

y^2+y=0

y(y+1)=0

y=0 or y=-1

3. Replace the values of y in equation (3) and solve for x

- For y=0

x^2=6+y

x^2=6

x=\sqrt{6} or x=-\sqrt{6}

- For y=-1

x^2=6+y

x^2=6-1

x^2=5

x=\sqrt{5} or x=-\sqrt{5}

So, the solutions of our system of equation are:

x=\sqrt{6}, y=0\\ x=-\sqrt{6} , y=0\\x=\sqrt{5} , y=-1\\x=-\sqrt{5} , y=-1

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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