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Leviafan [203]
3 years ago
12

Question in attachment answer with work no spam

Mathematics
1 answer:
Anastaziya [24]3 years ago
7 0
<span>The derivative of a function at a point gives the slope of the line tangent to the function's graph at that point. 

</span>Therefore, f'(2)  gives the slope of the tangent line to the graph of f where  x=2 , which is the point (2,3). 

We know this line passes through (2,3) , and we are also given that it passes through (7,6). <span>This should be enough to find the slope of that line. 

</span>\text{Slope} =  \dfrac{\text{change in y}}{\text{change in x}} 

\dfrac{6-3}{7-2} 

=  \dfrac{3}{5} 

In conclusion, f'(2)=\dfrac{3}{5}
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kenny6666 [7]
This problem can be solved in two ways, the long way, or the short way.

1. The long way
We know that the base of the triangle is along the x-axis, and the length of the base is 20.
The centre of mass is located at 2/3 of the distance from vertex (3,4) along the median, which cuts the base at (10,0).
Therefore the centre of mass is located at
x=3+(10-3)*2/3=23/3
y=4/3

2. The short way
It turns out that the centre of mass of a triangle sheet is located at the mean of the coordinates of the three vertices, i.e.
CG=((0+20+3)/3, (0+0+4)/3)=(23/3, 4/3)  as before.
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irinina [24]

Answer:

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Step-by-step explanation:

y--2=⅓(x-3)

y+2=⅓x-1

y=⅓x-1-2

y=⅓x-3

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