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Vinvika [58]
3 years ago
10

Please Help!!! I keep getting this answer wrong

Computers and Technology
1 answer:
IgorC [24]3 years ago
5 0

Answer:

I think its option a. and d.

Explanation:

option a. is right I'm sure.

option b. and c. are doubtful for me.

option d. can be true. but unlike a job letter, resumes carry a deeper view of the employee's accomplishments and qualifications.

but I still hold with option a. and b. if it's wrong please do inform, so I can refer.

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algol [13]

Answer:

can be used to make word docments look the same

Explanation:

4 0
3 years ago
Read 2 more answers
A binary tree is full if all of its vertices have either zero or two children. Let Bn denote the number of full binary trees wit
Arlecino [84]

Answer:

(a) B_3 = 1\\B_5 = 2\\B_7 = 5

(b) See attached

(c) B_n = 2^{(n-3)/2}

Explanation:

7 0
3 years ago
I need help plzzzzzzz
Aleonysh [2.5K]

By looking at your code, it seems like you're trying to let the user enter positive numbers until the user enters a negative number. To achieve this, you need to indent int(input("Enter a number, negative to stop")) inside the loop.

The second answer choice is correct.

3 0
3 years ago
Give a big-O estimate for the number additions used in this segment of an algorithm.
rjkz [21]
Big-O notation is a way to describe a function that represents the n amount of times a program/function needs to be executed. 

(I'm assuming that := is a typo and you mean just =, by the way) 

In your case, you have two loops, nested within each other, and both loop to n (inclusive, meaning, that you loop for when i or j is equal to n), and both loops iterate by 1 each loop.

This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.

HOWEVER, since the j-loop is nested within i-loop, the j-loop executes every time the i-loop <span>ITERATES. 
</span>
As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2). 

(tl;dr) In basic, it is O(n^2) because the loops are nested, meaning that the i-loop would be called n times, and for each iteration, it would call the j-loop n times, resulting in n*n runs.

A way to verify this is to write and test program the above. I sometimes find it easier to wrap my head around concepts after testing them myself.
3 0
3 years ago
A game design company develops a game in which players run a grocery store and need to keep tabs on the dollar amount of goods s
sdas [7]
I do believe it is Inventory management but I can never tell if it is the right answer. so my regards if it the wrong answer.

6 0
3 years ago
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