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a_sh-v [17]
3 years ago
14

What are the vertical asymptote(s) and hole(s) for the graph of y= x-1 over X squared + 6x+ 8

Mathematics
1 answer:
san4es73 [151]3 years ago
3 0

Answer:

You have vertical asymptotes on x=-4,-2

Step-by-step explanation:

This question is very simple. Since you have a denominator all you need to do is factor the bottom and find the zeros. When you factor the bottom of the equation you should get (x+4)(x+2). Now you have to set the bottom equal to zero to find the zeros. This means (x+4)=0 and (x+2)=0 So you get two answers x=-4 and x=-2 Therefore your two vertical asymptotes are on x-4,-2

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X + y = 152,<br><br> 8.5x + 12y = 1,656<br><br> How many hats were sold?
Elodia [21]

Answer:

x = 48 and y = 104

Step-by-step explanation:

Given equations are:

x+y = 152\\8.5x+12y=1656

From equation 1:

x = 152-y

Putting the value of y in equation 2

8.5(152-y)+12y = 1656\\1292-8.5y+12y = 1656\\3.5y+1292 = 1656\\3.5y = 1656-1292\\3.5y = 364\\\frac{3.5y}{3.5} = \frac{364}{3.5}\\y = 104

Now we have to put the value of y in one of the equation to find the value of x

Putting y = 104 in the first equation

x+y = 152\\x+ 104 = 152\\x = 152-104\\x = 48

Hence,

The solution of the system of equations is x = 48 and y = 104

The value of variable which was assumed for number of hats, is the total number of hats.

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Step-by-step explanation:

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