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a_sh-v [17]
3 years ago
14

What are the vertical asymptote(s) and hole(s) for the graph of y= x-1 over X squared + 6x+ 8

Mathematics
1 answer:
san4es73 [151]3 years ago
3 0

Answer:

You have vertical asymptotes on x=-4,-2

Step-by-step explanation:

This question is very simple. Since you have a denominator all you need to do is factor the bottom and find the zeros. When you factor the bottom of the equation you should get (x+4)(x+2). Now you have to set the bottom equal to zero to find the zeros. This means (x+4)=0 and (x+2)=0 So you get two answers x=-4 and x=-2 Therefore your two vertical asymptotes are on x-4,-2

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6 0
3 years ago
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