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3 years ago

9

Which of the following statements does not represent the same value as the others?

1 answer:

Semmy [17]3 years ago

5 0

the distance between 0 and −9

the absolute value of negative 9

the opposite of 9

the absolute value of 9

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A box of granola bars has 26 bars. If 7 friends split the bars equally, how many bars will be left?

Vinvika [58]

It will be 5 because 7x3 is 21, minus 26 to 21 is 5, won't be 7x4=28 and that's greater than 26

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3 years ago

(-6x) / (-2)<br> Simplify.<br><br> 12x<br> 4x<br> 3x<br> 1/12x

ElenaW [278]

$\dfrac{-6x}{-2}=\dfrac{-6}{-2}x=3x$

8 0

3 years ago

If you can help me that would be great the instructions are to factor these polynomial Don’t answer just to get pointsNO LINKS!!

natima [27]

Answer:

3. 3(x+y)(x-y)

4. (y²+4)(y+2)(y-2)

5. 2(3x+1)(x+2)

Step-by-Step:

3. 3(x²-y²) = 3(x+y)(x-y)

4. y⁴-16 = (y²+4)(y²-4)= (y²+4)(y+2)(y-2)

5. 6x²+14x+4 = 2(3x²+7x+2) = 2(3x+1)(x+2)

PLEASE RATE!!! I hope this helps!!!

If you have any question comment below

(I have verified my answers on an online calculator)

4 0

3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago

20 POINTS! Please help, best answer will recessive brainliest answer points as well as 5 stars and a thank you. :)

Vitek1552 [10]

Answer:

3): 14

Step-by-step explanation:

The problem states that ABC and DEF are similar. Therefore, dsue to similar triangles, we have 7x/7=4/x, so x^2=4. Therefore, x=2 (because x cannot be negative). Therefore, AB = 7x = 7*2=14

6 0

3 years ago