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Alex Ar [27]
2 years ago
10

What is an equation that goes through the points (4,10) and (3,-4)?

Mathematics
1 answer:
Svetlanka [38]2 years ago
4 0
Hmm could it be
y=14x-46 ? lmk
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HELP ASAP
Ludmilka [50]
The answer is a. Because when word phrases say “a number”, they are referring to the variable. For instance, x is the variable so x is “a number”.
8 0
3 years ago
Help me plzzz I need area and perimeter
Alexeev081 [22]

Answer:

Area = 37.5

Perimeter = 36

Step-by-step explanation:

Have a good day! :)

5 0
3 years ago
Read 2 more answers
A certain tennis player makes a successful first serve 6969​% of the time. Suppose the tennis player serves 9090 times in a matc
Wewaii [24]

Answer:

a) 4.387

b) Yes, because np & npq are greater than 10.

c) = 0.017          

Step-by-step explanation:

Give data:

p = 0.69

n = 90

a) a

E(X) = np = 62.1

SD(X) = \sqrt{(np(1-p))}

          =\sqrt{90\times 0.69(1- 0.69)}

          = 4.387

b)

np = 62.1  

q = 1 - p  = 1 - 0.69 = 0.31

npq = 19.251

Yes, because np & npq are greater than 10.

c.

P(X \geq 72   ) = P(X > 71.5) [continuity correction]

=    P(Z> \frac{((71.5-62.1)}{ 4.387})

= P(Z> 2.14 )      

= 1 - P(Z<2.14)              

= 1 - 0.983   (using table)          

= 0.017          

8 0
3 years ago
The perimeter of a playing field for a certain sport is 242 ft. the field is a​ rectangle, and the length is 47 ft longer than t
Mariulka [41]
242-94 = 148 (length is 47 more than the width, you double the length to get the perimeter, so you double 47 which equals 94)
148/4 = 37 (4 being the 4 sides of the rectangle)

width = 37
length = 84

4 0
3 years ago
A solid metal cube of side 3 inches is placed in a rectangular tank whos length, width, and height are 3, 4 and 5 inches, respec
Black_prince [1.1K]
To solve this problem you must apply the proccedure shown below:

 1. Yoy have that the <span>rectangular tank has the following dimensions:

 Length=3 inches
 Widht=4 inches
 Height=5 inches

 2. Then, its volume is:

 V1=LxWxH
 V1=3 inchesx4 inchesx5 inches
 V=60 inches</span>³

 3. The sides of the <span>solid metal cube are of 3 inches, therefore, its volume is:

 V2=s</span>³
 V2=(3 inches)³
 V2=27 inches³

 4. T<span>he volume, in cubic inches, of water that the tank can now hold is:

 Vt=V1-V2
 Vt=60 inches</span>³-27 inches³
 Vt=33 inches³
5 0
3 years ago
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