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vodomira [7]
3 years ago
14

Line l has a slope of 98. The line through which of the following pair of points is perpendicular to l? A. (−9,−6),(3,3) B. (9,−

2),(−6,6) C. (−5,−6),(3,3) D. (3,−5),(−6,3)
Mathematics
2 answers:
Valentin [98]3 years ago
6 0

We can employ some logic to reduce the answers we need to test. We know that the slope perpendicular to line l has to have a negative reciprocal slope, so a slope of-\frac{9}{8}. We see that in A and C, as x increases so does y. That means the slope of these equations are positive, which we don't want. Now for some algebra:

m=\frac{y_2-y_1}{x_2-x_1} \implies\\ B. \frac{6+2}{-6-9}=\frac{8}{-15} \\ D. \frac{3+5}{-6-3}=-\frac{8}{9}

We se that D has the correct slope so that must be the answer.

prohojiy [21]3 years ago
3 0

m =( Y2 - Y1)/ (X2-X1)

m =( 3-(-5))/ (-6-3)

m = - 8/9

I am assuming you meant a slope of 9/8 in your original question, so the points perpendicular to I are answer D.

Perpendicular means the slope is opposite reciprocal.

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(0, 1) and (2,4)

slope = (4 - 1)/(2 - 0) = 3/2

Answer

C.) 3/2

7 0
4 years ago
Solve <br><br> 5x + 3 = x + 11
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Step-by-step explanation:

5x + 3 = x + 11

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agasfer [191]
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The value of 3' x10, when x = -2, can be
Mkey [24]

Answer:

a = 8 and b = 2

Step-by-step explanation:

Given

\sqrt[3]{x^{10}}

x = -2

Required

Express as: a\sqrt[3]{b}

Substitute -2 for x in \sqrt[3]{x^{10}}

\sqrt[3]{x^{10}} = \sqrt[3]{(-2)^{10}}

\sqrt[3]{x^{10}} = \sqrt[3]{1024}

Express 1024 as 2^10

\sqrt[3]{x^{10}} = \sqrt[3]{2^{10}}

Apply law of indices:

\sqrt[3]{x^{10}} = \sqrt[3]{2^{9+1}}

Apply law of indices: Split

\sqrt[3]{x^{10}} = \sqrt[3]{2^{9}*2^1}}

\sqrt[3]{x^{10}} = \sqrt[3]{2^{9}} *\sqrt[3]{2^1}}

\sqrt[3]{x^{10}} = \sqrt[3]{2^{9}} *\sqrt[3]{2}}

\sqrt[3]{x^{10}} = 2^{9*\frac{1}{3}}} *\sqrt[3]{2}}

\sqrt[3]{x^{10}} = 2^3 *\sqrt[3]{2}}

\sqrt[3]{x^{10}} = 8\sqrt[3]{2}}

By comparison:

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8 0
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