Make p the subject, 4(p - 2q) = 3p + 2

Mathematics

1 answer:

Jobisdone [24]3 years ago

8 0

4(p-2q) = 3p+2

subtracting 2 by both sides,

4(p-2q) = 3p

Dividing 3,

4(p-2q)/3 = p

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Find the area of the shaded region.f(x)=4x+3x2−x3,g(x)=0<br> The area is _____.

Tasya [4]

Answer:

The answer is " $\bold{\frac{7}{2}}$ "

Step-by-step explanation:

Given value:

$\to f(x)=4x+3x^2-x^3\\\\\to g(x)=0$

Find:

area=?

calculation:

$\ Area = \int_{-1}^{0} -(4x+3x^2-x^3) dx + \int_{0}^{1} (4x+3x^2-x^3) dx \\\\$

$= -(2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= -( 2x^2+x^3- \frac{x^4}{4})_{-1}^{0} + (2x^2+x^3- \frac{x^4}{4})_{0}^{1}\\\\\\= ( 2- 1 -\frac{1}{4}) + (2+1- \frac{1}{4})\\\\\\= ( \frac{8-4-1}{4}) + (\frac{8+4-1}{4})\\\\= ( \frac{3}{4}) + (\frac{11}{4})\\\\= \frac{3}{4} + \frac{11}{4}\\\\= \frac{11+3}{4}\\\\= \frac{14}{4}\\\\= \frac{7}{2}\\\\$