Answer:
The vertex of this parabola, , can be found by completing the square.
Step-by-step explanation:
The goal is to express this parabola in its vertex form:
,
where , , and are constants. Once these three constants were found, it can be concluded that the vertex of this parabola is at .
The vertex form can be expanded to obtain:
.
Compare that expression with the given equation of this parabola. The constant term, the coefficient for , and the coefficient for should all match accordingly. That is:
.
The first equation implies that is equal to . Hence, replace the "" in the second equation with to eliminate :
.
.
Similarly, replace the "" and the "" in the third equation with and , respectively:
.
.
Therefore, would be equivalent to . The vertex of this parabola would thus be:
.
L=w+4 this shows the length is 4 inches longer than width
h=w-2 this shows the height is 2 inches shorter than the width
volume=lwh
so 240=lwh=(w+4)(w)(w-2)
simplify and solve to find the width then you can use that to find the other values as well.
It is not a function and that is becuase a vertical line would pass through it twice
Answer:
\left(ax^2\right)\left(-6x^b\right)=12x^5\\\\(-6a)x^{2+b}=12x^5\to -6a=12\ and\ 2+b=5\\\\-6a=12\ \ \ |:(-6)\\a=-2\\\\2+b=5\ \ \ |-2\\b=3
Answer:\ a=-2;\ b=3
Step-by-step explanation: