All categories

3 years ago

X + 78 = 90 can someone solve this for me please?

Mathematics

1 answer:

kondaur [170]3 years ago

8 0

Let's solve your equation step-by-step.

x+78=90

Step 1: Subtract 78 from both sides.

x+78−78=90−78

x=12

Please put brainliest!

You might be interested in

This? .......................................................

adelina 88 [10]

Answer:

109.6

Step-by-step explanation:

3 0

3 years ago

The heights of a certain type of tree are approximately normally distributed with a mean height p = 5 ft and a standard

arsen [322]

Answer:

A tree with a height of 6.2 ft is 3 standard deviations above the mean

Step-by-step explanation:

⇒ $1^s^t$ statement: A tree with a height of 5.4 ft is 1 standard deviation below the mean(FALSE)

an X value is found Z standard deviations from the mean mu if:

$\frac{X-\mu}{\sigma} = Z$

In this case we have: $\mu=5\ ft$ $\sigma=0.4\ ft$

We have four different values of X and we must calculate the Z-score for each

For X =5.4\ ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.4-5}{0.4}=1$

Therefore, A tree with a height of 5.4 ft is 1 standard deviation above the mean.

⇒ $2^n^d$ statement:A tree with a height of 4.6 ft is 1 standard deviation above the mean. (FALSE)

For X =4.6 ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{4.6-5}{0.4}=-1$

Therefore, a tree with a height of 4.6 ft is 1 standard deviation below the mean .

⇒ $3^r^d$ statement:A tree with a height of 5.8 ft is 2.5 standard deviations above the mean (FALSE)

For X =5.8 ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{5.8-5}{0.4}=2$

Therefore, a tree with a height of 5.8 ft is 2 standard deviation above the mean.

⇒ $4^t^h$ statement:A tree with a height of 6.2 ft is 3 standard deviations above the mean. (TRUE)

For X =6.2\ ft

$Z=\frac{X-\mu}{\sigma}\\Z=\frac{6.2-5}{0.4}=3$

Therefore, a tree with a height of 6.2 ft is 3 standard deviations above the mean.

6 0

3 years ago

Solutions of 3x+2y=4 and 6x+4y=8

Alecsey [184]

Answer:

Infinite solutions

Step-by-step explanation:

1) First, you can solve this easily by elimination. Multiply the first equation by -2 in order to cancel out terms when adding to the second equation.

2) Then, add the new set of equations together. However, everything cancels out, bringing us to 0 = 0. This means that the lines the equations make must be the same. Thus, all real numbers must make this equation true, meaning that there are infinite solutions.