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Zolol [24]
3 years ago
11

A container of oil has spilled on a concrete floor. The oil flow can be expressed with the function n(t) = 7t, where t represent

s time in minutes and n represents how far the oil is spreading.
The flowing oil is creating a circular pattern on the concrete. The area of the pattern can be expressed as A(n) = πn2.

Part A: Find the area of the circle of spilled oil as a function of time, or A[n(t)]. Show your work. (6 points)

Part B: How large is the area of spilled oil after 8 minutes? You may use 3.14 to approximate π in this problem. (4 points)
Mathematics
1 answer:
nadezda [96]3 years ago
3 0
Given:
Oil flow: n(t) = 7t  where t is time and n = how far the oil is spreading
Area of the circular pattern the oil is forming:
A(n) = πn²


<span>Part A: Find the area of the circle of spilled oil as a function of time, or A[n(t)]

A[n(t)] = </span>π (7t)² = π * 49 * t²

<span>How large is the area of spilled oil after 8 minutes? 

n(t) = 7t </span>→ 7 * 8 = 56

A(56) = 3.14 * 56² = 9,847.04 square units

or

A[n(t)] = π (7t)² 
A[n(8)] = 3.14 * (7*8)² = 3.14 * 3,136 = 9,847.04 square units

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The expression into a single logarithm is log[(x)^{10}][(2)^{30}]

Step-by-step explanation:

Let us revise some logarithmic rules

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- At first re-write 10 log(x)

∴  10 log(x) = log(x)^{10}

- Then re-write 5 log(64)

∴  5 log(64) = log(64)^{5}

∴ 10 log(x) + 5 log(64) = log(x)^{10} + log(64)^{5}

- Use the 3rd rule above to make it single logarithm

∵ log(x)^{10} + log(64)^{5} = log[(x)^{10}][(64)^{5}]

∴ 10 log(x) + 5 log(64) = log[(x)^{10}][(64)^{5}]

∵ 64 = 2 × 2 × 2 × 2 × 2 × 2

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- Multiply the two powers of 2

∴ (64)^{5}=(2)^{30}

∴ 10 log(x) + 5 log(64) = log[(x)^{10}][(2)^{30}]

The expression into a single logarithm is log[(x)^{10}][(2)^{30}]

Learn more:

You can learn more about the logarithmic functions in brainly.com/question/11921476

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Please Help, I am very grateful for anything
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Step-by-step explanation:

m∠A=1/2(KW)

Sub: x+45=1/2(x+20+3x)

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sejalbandil

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