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4 years ago

What is the difference between 10/3 and 3/2

Mathematics

2 answers:

taurus [48]4 years ago

4 0

Answer:

1 5/6

Step-by-step explanation:

To subtract fractions, change the base number to the same number (denominator) by multiplying the same number to the numerator and denominator

10/3-3/2=20/6-9/6

=11/6

1 5/6

Rudiy274 years ago

3 0

Answer:

$\frac{11}{6}$

Step-by-step explanation:

Part 1

Look for a common denominator between the two #s. Let's put 6 as the common denominator.

10/3:

The denominator 3, times 2 equals 6 so, multiply the numerator by 2 also.

So, 10/3 is equivalent to 20/6.

3/2:

The denominator 2, times 3 equals 6 so, multiply the numerator by 3 also.

So, 3/2 is equivalent to 9/6.

Part 2

Find the difference between the fractions by subtracting them:

$\frac{20}{6} - \frac{9}{6} = \frac{11}{6}$

Your answer is 11/6

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Write a recursive formula for each explicit formula

Crazy boy [7]

Answer:

38. $a_1=107,\ a_n=a_{n-1}-1$

40. $a_1=87,\ a_n=a_{n-1}+52$

Step-by-step explanation:

38. Given explicit formula:

$a_n=108-n$

When $n=1,$ then $a_1=108-1=107$

When $n=2,$ then $a_2=108-2=106$

When $n=3,$ then $a_3=108-3=105$

When $n=4,$ then $a_4=108-4=104$

and so on

You can see that each next number is 1 less than previous number, so the recursive formula is

$a_n=a_{n-1}-1$

40. Given explicit formula:

$a_n=35+52n$

When $n=1,$ then $a_1=35+52\cdot 1=87$

When $n=2,$ then $a_2=35+52\cdot 2=139$

When $n=3,$ then $a_3=35+52\cdot 3=191$

When $n=4,$ then $a_4=35+52\cdot 4=243$

and so on

You can see that each next number is 52 more than previous number, so the recursive formula is

$a_n=a_{n-1}+52$

8 0

3 years ago

An accounting professor is notorious for being stingy in giving out good letter grades. In a large section of 140 students in th

Arlecino [84]

Answer:

The 95% confidence interval for the proportion of students that obtain a letter grade of B or better from this professor is (0.2056, 0.3544). The interpretation is that we are 95% sure that the true proportion of students who obtain a letter grade of B or better from this professor is between 0.2056 and 0.3544.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.