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77julia77 [94]
3 years ago
6

What is the focus of the parabola given by `-(1)/(4)(y + 2)^2 = (x −1)`? A. (-1, 2) B. (1, -2) C. (0, -2) D. (0, 2)

Mathematics
2 answers:
katrin [286]3 years ago
5 0

The correct answer is that the focus is, <u><em>(0,−2)</em></u>

Amanda [17]3 years ago
5 0

Answer:

The correct option is C.

Step-by-step explanation:

The given equation is

-\frac{1}{4}(y+2)^2=(x-1)

Multiply both the sides by -4.

(y+2)^2=-4(x-1)            .... (1)

Where, (h,k) is vertex and (h+p,k) is focus.

The standard form of a parabola is

(y-k)^2=4p(x-h)              ..... (2)

From (1) and (2), we get

k=-2,h=1,4p=-4\Rightarrow p=-1

The focus of the parabola is

(h+p,k)=(1-1,-2)=(0,-2)

The focus of the given parabola is (0,-2). Therefore the correct option is C.

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Dominik [7]

Answer:

Step-by-step explanation:

h^2=x^2+y^2, here x and y are equal so we can say

h^2=2x^2, we see that h=2(2^(1/2)) so

2x^2=8

x^2=4

x=2

4 0
3 years ago
A television game has 6 shows doors, of which the contests must pick 2. behind two of the doors are expensive cars, and behind t
Katyanochek1 [597]
The answer to this question:
One car probability 82/120
No car probability = 24/120
At least one car probability= 96/120

I will focus answering the 3 doors probability since the 2nd door problem is solved in the previous problem. (brainly.com/question/5761449)

No car condition
1. 1st door consolation, 2nd door consolation=, 3rd door consolation= 4/6 * 3/5 * 2/4= 24/120
This was also can be found by: (4!/1!)/ (6!/3!) = 24/120

(At least one car probability)  is the opposite of (no car probability) In this case, the easier way is 
100% - (no car probability) = 120/120 - 24/120= 96/120

One car probability is (At least one car probability) - (2 car probability). It will be easier to count the 2 car probability and subtract the (At least one car probability) 
Two car condition:
1. 1st door car, 2nd door car, 3rd door consolation = 2/6 * 1/5 * 4/4 =8/ 120
2.1st door car, 2nd door consolation, 3rd door car =2/6 * 4/5 * 1/4 = 8/120
3. 1st door consolation, 2nd door car, 3rd door car= 4/6 * 2/5 * 1/4= 8/120
The total probability will be 8/120+ 8/120 + /120= 24/120
This was also can be found by: (2!) (4!/2!)/ (6!/3!) = 24/120

One car probability =  (At least one car probability) - (2 car probability)= 96/120-24/120= 82/120
3 0
3 years ago
Help me pleaseeee<br> it’s algebra 2
aivan3 [116]
The answer is yes. I already answered this lol
4 0
2 years ago
3/5 of a number decreased by one is 23. What is the number?
garri49 [273]
You can set up an equation based off of the information given:

x represents the unknown number

3/5x - 1 = 23

add 1 to both sides to isolate the 3/5x

3/5x = 24

divide both sides by 3/5 to solve for x

x = 120/3

120/3 can be simplified into 40

Final answer: x = 40
5 0
3 years ago
Find the missing exponent. 2^{3}\cdot 2^{?}=2^{10}2
guapka [62]

Answer:

7

Step-by-step explanation:

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When multiplying exponents, the exponents add up together. In other words, just subtract 10-3 = 7 that would be your missing exponent!

Hope this helps, good luck!

5 0
2 years ago
Read 2 more answers
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