Parametrizations help needed

Mary is making some shirts for her school’s drama department. De fabric store has three and one sixths yards of the fabric she w

Keith_Richards [23]

6 and one third. Hope this helps!

4 0

3 years ago

Help me with this question if you don’t mind

vampirchik [111]

Answer:

D

Step-by-step explanation:

if AB is congruent to AC that means both are 76 degrees so subtract that from the total degrees of a whole triangle which is 180 that gives you A which is 28.

Hope it helps :)

5 0

3 years ago

Which angles are supplementary

Naddik [55]

Answer:

∆pkl and ∆nkl

Step-by-step explanation:

Supplementary angles are two angles whose measures add up to 180° . The two angles of a linear pair , like ∠pkl and ∠nkl in the figure above, are always supplementary.

3 0

2 years ago

nicole is flying two kites. she has 104 feet of string out to one kite and 110 feet out to the other kite. the angle formed by t

tankabanditka [31]

Answer:

Step-by-step explanation:

Answer:

48.49 feet

Step-by-step explanation:

The diagrammatic sketch of the details given in the question was attached in the picture below.

From the picture below, the distance between the two kites is represented by (c) and can be calculated by using the cosine angle rule which is illustrated as:

$c^2 = a^2 + b^2 -2ab cos \ C$

where;

a = 110

b = 104

Cos C = 26°

Then;

$c^2 = 110^2 + 104^2 -2(110)(104) cos \ 26 \\ \\ c^2 = 12100 + 10816- 22880 ( 0.8988) \\ \\ c^2 = 22916- 20564.544 \\ \\ c^2 = 2351.456 \\ \\ c= \sqrt{2351.456} \\ \\ \mathbf{ c = 48.49 \ feet}$

8 0

3 years ago

For which system of equations is (5, 3) the solution? A. 3x – 2y = 9 3x + 2y = 14 B. x – y = –2 4x – 3y = 11 C. –2x – y = –13 x

Alla [95]

The correct answer is:

D) $\left \{ {{2x-y=7} \atop {2x+7y=31}} \right.$ .

Explanation:

We solve each system to find the correct answer.

For A:
$\left \{ {{3x-2y=9} \atop {3x+2y=14}} \right.$

Since we have the coefficients of both variables the same, we will use elimination to solve this.

Since the coefficients of y are -2 and 2, we can add the equations to solve, since -2+2=0 and cancels the y variable:
$\left \{ {{3x-2y=9} \atop {+(3x+2y=14)}} \right. 
\\
\\6x=23$

Next we divide both sides by 6:
6x/6 = 23/6
x = 23/6

This is not the x-coordinate of the answer we are looking for, so A is not correct.

For B:
$\left \{ {{x-y=-2} \atop {4x-3y=11}} \right.$

For this equation, it will be easier to isolate a variable and use substitution, since the coefficient of both x and y in the first equation is 1:
x-y=-2

Add y to both sides:
x-y+y=-2+y
x=-2+y

We now substitute this in place of x in the second equation:
4x-3y=11
4(-2+y)-3y=11

Using the distributive property, we have:
4(-2)+4(y)-3y=11
-8+4y-3y=11

Combining like terms, we have:
-8+y=11

Add 8 to each side:
-8+y+8=11+8
y=19

This is not the y-coordinate of the answer we're looking for, so B is not correct.

For C:
Since the coefficient of x in the second equation is 1, we will use substitution again.

x+2y=-11

To isolate x, subtract 2y from each side:
x+2y-2y=-11-2y
x=-11-2y

Now substitute this in place of x in the first equation:
-2x-y=-13
-2(-11-2y)-y=-13

Using the distributive property, we have:
-2(-11)-2(-2y)-y=-13
22+4y-y=-13

Combining like terms:
22+3y=-13

Subtract 22 from each side:
22+3y-22=-13-22
3y=-35

Divide both sides by 3:
3y/3 = -35/3
y = -35/3

This is not the y-coordinate of the answer we're looking for, so C is not correct.

For D:
Since the coefficients of x are the same in each equation, we will use elimination. We have 2x in each equation; to eliminate this, we will subtract, since 2x-2x=0:

$\left \{ {{2x-y=7} \atop {-(2x+7y=31)}} \right. 
\\
\\-8y=-24$

Divide both sides by -8:
-8y/-8 = -24/-8
y=3

The y-coordinate is correct; next we check the x-coordinate Substitute the value for y into the first equation:
2x-y=7
2x-3=7

Add 3 to each side:
2x-3+3=7+3
2x=10

Divide each side by 2:
2x/2=10/2
x=5

This gives us the x- and y-coordinate we need, so D is the correct answer.

7 0

3 years ago