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erik [133]
4 years ago
14

Parametrizations help needed

Mathematics
1 answer:
erica [24]4 years ago
6 0
Sorry I don't know that either
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Solve this linear equation for p: 2.6(5.5p – 12.4) = 127.92 1. Distributive property: 2. Addition property of equality: 3. Divis
Ronch [10]

P= 11.2

Not sure why you took p out of the equation.

2.6(5.5p-12.4)=127.92

14.3p - 32.24 =127.92

14.3p = 160.16

P = 11.2

4 0
3 years ago
Read 2 more answers
Find an equation of a polynomial function with real coefficients having zeros 4 and 2+3i.
maks197457 [2]

Answer:

Step-by-step explanation:

6 0
3 years ago
DJ has $24 more than twice as much as Tucker. Together they have $132. How much does DJ have?
Elanso [62]
$84 because you do 132 - 24 then rhat answer- 24
6 0
4 years ago
Yo can someone please help and fast PLEASE
Illusion [34]

Answer:

It's incorrect because the equation is solve incorrectly the anwer is r= -4

Step-by-step explanation:

Add 4r4r to both sides.

-3r+9+4r=5

−3r+9+4r=5

2 Simplify  -3r+9+4r−3r+9+4r  to  r+9r+9.

r+9=5

r+9=5

3 Subtract 99 from both sides.

r=5-9

r=5−9

4 Simplify  5-95−9  to  -4−4.

r=-4

r=−4

6 0
3 years ago
Simplify each expression.
umka21 [38]
half\to\frac{1}{2}\\the\ sum\ of\ p\ and\ 2q\to p+2q\\increased\to"+"\\three-fourts\ q\to\frac{3}{4}q\\\\an\ expression:\\\\\frac{1}{2}(p+2q)+\frac{3}{4}q\ \ \ |use\ distributive\ property:a(b+c)=ab+ac\\\\=\frac{1}{2}(p)+\frac{1}{2}(2q)+\frac{3}{4}q=\frac{1}{2}p+q+\frac{3}{4}q=\huge\boxed{\frac{1}{2}p+1\frac{3}{4}q}
5 0
3 years ago
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