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USPshnik [31]
3 years ago
14

Pls help i need answer

Mathematics
2 answers:
laiz [17]3 years ago
6 0

Answer:

b. 14 m

Step-by-step explanation:

base of left side triangle

  • √20²-12²= √256= 16 m

base of right  side triangle

  • 24-16= 8 m

missing length

  • √12²+8²= √208= 14.42 m

Option b. 14 m is closest one

saul85 [17]3 years ago
3 0

Answer:

14m

Step-by-step explanation:

Step1:

<u>C</u><u>onsider the first right angled triangle using Pythagoras Theorem:</u>

(hyponenus)^2 = (opposite)^2 + (adjacent)^2

20^2 = 12^2 + A^2

A^2 = 400 - 144 = 256

A = Square root of 256 = 16m

Step2:

<u>CONSIDER THE SECOND RIGHT_ ANGLED TR</u><u>I</u><u>A</u><u>N</u><u>G</u><u>L</u><u>E</u><u>:</u>

<u>a</u><u>d</u><u>j</u><u>a</u><u>c</u><u>e</u><u>n</u><u>t</u><u>=</u><u>2</u><u>4</u><u>-</u><u>1</u><u>6</u><u>=</u><u>8</u><u>m</u>

<u>o</u><u>p</u><u>p</u><u>o</u><u>s</u><u>i</u><u>t</u><u>e</u><u>=</u><u>1</u><u>2</u><u>m</u>

Hypotenus=?

<u>(hypo</u><u>t</u><u>enus)^2 = (opposite)^2 + (adjacent)^2</u>

<u>H</u><u>^</u><u>2</u><u>=</u><u>1</u><u>2</u><u>^</u><u>2</u><u>+</u><u>8</u><u>^</u><u>2</u><u>=</u>

<u>1</u><u>4</u><u>4</u><u>+</u><u>6</u><u>4</u>

<u>H</u><u>^</u><u>2</u><u>=</u><u>2</u><u>0</u><u>8</u>

<u>H</u><u>=</u><u>s</u><u>q</u><u>u</u><u>a</u><u>r</u><u>e</u><u> </u><u>r</u><u>o</u><u>o</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>2</u><u>0</u><u>8</u><u>=</u><u>1</u><u>4</u><u>.</u><u>4</u><u>2</u><u>m</u>

<u>T</u><u>o</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>n</u><u>e</u><u>a</u><u>r</u><u>e</u><u>s</u><u>t</u><u> </u><u>m</u><u>e</u><u>t</u><u>e</u><u>r</u><u>=</u><u>1</u><u>4</u><u>m</u>

<u>H</u><u>o</u><u>p</u><u>e</u><u> </u><u>i</u><u>t</u><u> </u><u>h</u><u>e</u><u>l</u><u>p</u><u>s</u><u>.</u>

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