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olya-2409 [2.1K]
3 years ago
15

6,7,9 pleaseee !!!! I need help today I need it for tomorrow morning

Mathematics
2 answers:
marin [14]3 years ago
7 0
Can you take another fully picture plez

Advocard [28]3 years ago
4 0
Cant see the entire question at the bottom
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Solve for t<br><br><br>t - 3= −1
frutty [35]

Answer:

t = 2

Step-by-step explanation:

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357288737773*34616 please help me
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Step-by-step explanation:

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What is the simplified form of the quantity of x plus 4, all over the quantity of 7 − the quantity of x plus 3, all over the qua
scoundrel [369]
\frac{x + 4}{7} -\frac{x + 3}{x + 5} =\frac{(x + 4)(x + 5)}{7(x + 5)} -\frac{7(x + 3)}{7(x + 5)} =\frac{x(x + 5) + 4(x + 5)}{7(x) + 7(5)} - \frac{7(x) + 7(3)}{7(x) + 7(5)} =\frac{x(x) + x(5) + 4(x) + 4(5)}{7x + 35} - \frac{7x + 21}{7x + 35} =\frac{x^{2} + 5x + 4x + 20}{7x + 35} -\frac{7x + 21}{7x + 35} =\frac{x^{2} + 9x + 20}{7x + 35} - \frac{7x + 21}{7x + 35} =\frac{(x^{2} + 9x + 20) - (7x + 21)}{7x + 35} =\frac{x^{2} + (9x - 7x) + (20 - 21)}{7x + 35} =\frac{x^{2} + 2x -1}{7x + 35}
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2 years ago
Which of the following is NOT a linear factor of the polynomial function?
Natalija [7]

Answer:

Among the four choices, (x + 5) is the only one that is not a linear factor of this polynomial function.

Step-by-step explanation:

Let a denote some constant. A linear factor of the form (x - a) is a factor of a polynomial f(x) if and only if f(a) = 0 (that is: replacing all x in the polynomial f(x) \! with the constant a\! would give this polynomial a value of 0.)

For example, in the second linear factor (x - 2), the value of the constant is a = 2. Verify that the value of f(2) is indeed 0. (In other words, replacing all x in the polynomial f(x) \! with the constant 2 should give this polynomial a value of 0\!.)

\begin{aligned}f(2) &= 2^3 - 5\times 2^2 - 4 \times 2 + 20 \\ &= 8 - 20 - 8 + 20 \\ &= 0 \end{aligned}.

Hence, (x - 2) is indeed a linear factor of polynomial f(x).

Similarly, it could be verified that (x - 5) and (x + 2) are also linear factors of this polynomial function.

Rewrite the first linear factor (x + 5) in the form (x - a) for some constant a: (x + 5) = (x - (-5)), where a = -5.

Calculate the value of f(5).

\begin{aligned}f(5) &= (-5)^3 - 5\times (-5)^2 - 4 \times (-5) + 20 \\ &= (-125) - 125 + 20 + 20 \\ &= -210\end{aligned}.

f(5) \ne 0 implies that (x - (-5)) (which is equivalent to (x + 5)) isn't a linear factor of this polynomial function.

3 0
2 years ago
Help me plsss i am soo bad at this
lara [203]

Step-by-step explanation:

GIVEN: O is the mid point of AC & BD.

Therefore, AO = CO & BO = DO

\therefore \: AO   \: \cong \: CO.. (given) \\  \\  \:  \:  \:  \:  \angle \: AOB  \: \cong \:\angle \:COD\\..(vertically\:opposite\:angles) \:  \\  \\  \& \: \:  \:   BO  \: \cong \: DO.. (given)  \\  \\  \therefore \triangle \: AOB  \:  \cong \:  \triangle \:COD  \\ ..(by \: SAS \: test  \: of  \: congruence ) \\  \\   \therefore AB =  CD.. \\ (Corresponding  \: sides  \: of  \: congruent  \: triangles)

8 0
2 years ago
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