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olya-2409 [2.1K]
3 years ago
15

6,7,9 pleaseee !!!! I need help today I need it for tomorrow morning

Mathematics
2 answers:
marin [14]3 years ago
7 0
Can you take another fully picture plez

Advocard [28]3 years ago
4 0
Cant see the entire question at the bottom
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3 years ago
Please help me....I really need help!!
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\dfrac{c^2-4}{6c^4+15c^3}\div\dfrac{c^2+4c+4}{12c^3+30c^2}=\dfrac{c^2-2^2}{3c^3(2c+5)}\div\dfrac{c^2+2(c)(2)+2^2}{6c^2(2c+5)}\\\\_{\text{use}\ a^2-b^2=(a-b)(a+b)\ \text{and}\ (a+b)^2=a^2+2ab+b^2}\\\\=\dfrac{(c-2)(c+2)}{3c^3(2c+5)}\cdot\dfrac{6c^2(2c+5)}{(c+2)^2}=\dfrac{(c-2)}{c}\cdot\dfrac{2}{(c+2)}=\boxed{\dfrac{2(c-2)}{c(c+2)}}

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That is impossible to answer because this is an expression. you can only solve for x in equations
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