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Grace [21]
3 years ago
12

In fruit flies, the gene for red eyes (R) is dominant and the gene for sepia eyes (r) is recessive. If two red-eyed heterozygous

flies (Rr) mate together, what are the possible genotypes of their offspring? (Hint: You many want to complete a Punnett square.) RR and Rr Rr only RR and rr RR, Rr, and rr
Biology
1 answer:
maw [93]3 years ago
6 0
So here we have two heterozygous organisms that will mate. You can put them into a Punnet square, just to be sure of your answers and to find all possible genotypes : 

      R      r
R  RR   Rr
r   Rr     rr

So you have RR, Rr and rr as your possible genotypes. 
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If you have a pet cockroach with a brown body, how could you find out if it is
aleksklad [387]

Answer:

by testcrossing with a homozygous recessive partner

Explanation:

<u>If a pet cockroach exists whose zygosity is unknown, this can be determined by a test cross. A test cross involves crossing an organisms whose zygosity is unknown with a partner that is homozygous recessive for the same trait.</u>

Let us assume that brown body is represented by the allele B, the dominant allele. The homozygous recessive version would be bb.

The genotype of a brown cockroach whose zygosity is not known can be denoted as B_, where '_' can be a 'B' or a 'b'.

When B_ is crossed with bb:

B_   x   bb

Progeny

2 Bb

2 _b

The phenotype of Bb would be brown (since B is dominant over b) while the phenotype of _b would depend on the zygosity level of the cockroach.

If the unknown genotype is BB, then _b becomes Bb and the phenotype will be a brown body. This means that all the progeny will appear brown. (<em>see the first attached image for the Punnet's square</em>)

In other word, if the unknown genotype is bb, then _b becomes bb and the phenotype will be a alternate color (non-brown) body. This means that 50% of the progeny will appear brown while the remaining 50% will be in the alternate color. (<em>attached</em>

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