To answer the question above, we will have to use some calculus approach to this problem.
<span>volume of sphere = (4/3)(pi)(radius^3) = (4/3)(pi)(9^3) = 972pi </span>
<span>mass = (density)(volume) = (972pi)(1,000) = 972,000pi </span>
<span>force = (mass)(acceleration or gravity here) = (972,000pi)(9.8) = 9,525,600pi </span>
<span>work = (force)(distance) = (9,525,600pi)(4.5) = 42,865,200pi J
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I hope my answer helped you with your problem
Answer:
dy/dt = - (1/5) ft/s = - 0.2 ft/s
Step-by-step explanation:
Given
L = 5 ft
Qin = 25 ft³/s
Qout = 30 ft³/s
h = 10 ft
dy/dt = ?
We can apply the relation
ΔQ = Qint - Qout = 25 ft³/s - 30 ft³/s
⇒ ΔQ = - 5 ft³/s
Then we use the formula
Q = v*A
where Q = ΔQ, A = L² is the area of square base and v = dy/dt is the rate of change in the depth of the solution in the tank
⇒ ΔQ = (dy/dt)*L²
⇒ dy/dt = ΔQ/L²
⇒ dy/dt = (- 5 ft³/s)/(5 ft)²
⇒ dy/dt = - (1/5) ft/s = - 0.2 ft/s
Answer:
Step-by-step explanation:
The area of a rectangle is given by 
. Therefore, we can set up the following inequality:
.
Solving this inequality, we have:
.
Therefore, the largest length Carmen's painting can be is 
.
Answer:
56 decreases to 11 because 45 was subtracted from it.
56-45=11
