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2 years ago

Evaluate the following expression: (3 · 3)2 - 23

2 answers:

5 0

3 times 3 equals 9 and 2-23 equals 21

or you’re probably distributing so 3 times 2 equals 6 now 3 times 3 times -23 equals -69
basically the same thing all over again so sorry I tried to help

Kruka [31]2 years ago

4 0

This is really hard I’m going to help you just let me do the work

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If Mitch bicycles at an avenger speed of 18 miles per hour,how long will it take him to cover 76.5 miles?

Lisa [10]

Answer:

Step-by-step explanation:

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2 years ago

Suppose that IQ scores have a bell-shaped distribution with a mean of 100 and a standard deviation of 14. Using the empirical ru

Brut [27]

Answer:

99.7%

Step-by-step explanation:

Bell shaped curve by empirical rule is that if the standard deviation from the mean (left to right) is 1 deviation then about 68% of the data is in that range if it’s 2 standard deviations away then it’s 95% and 3 deviations away is 99.7%

142-100=42=3(14)

100-58=42=3(14)

Therefore the data is three standard deviations from the mean and this there is 99.7% of the data in this range.

3 0

2 years ago

A 54-foot guy wire is attached to a utility pole to provide support for the pole. The wire forms a 60º angle with the ground. Ho

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Answer:

22 $\sqrt{x} 2$

Step-by-step explanation:

should be the answer if im correct

6 0

2 years ago

True or False- You can use the distributive property to help you expand and<br> factor expressions.

vladimir2022 [97]

Answer:

true

Step-by-step explanation:

8 0

2 years ago

A baseball diamond is a square with side 90 ft. A batter hits the ball and runs toward first base with a speed of 31 ft/s. (a) A

Afina-wow [57]

Answer:

13.86 ft/sec

Step-by-step explanation:

If we let x = distance batter has run at time t and D = distance from second base to the batter at time t, then we know $\frac{dx}{dt}=31 ft/s$ and we want $\frac{dD}{dt}$ when he is halfway (at x = 45).

Using Pythagoras theorem

$D^2=90^2+(90-x)^2\\\text{Differentiating with respect to t}\\2D\frac{dD}{dt}=0+2(90-x)(-1)\frac{dx}{dt}\\2D\frac{dD}{dt}=-2(90-x)\frac{dx}{dt}$

When x=45

$D^2=90^2+(90-x)^2\\D^2=90^2+(90-45)^2\\D^2=10125\\D=\sqrt{10125}$

$2D\frac{dD}{dt}=-2(90-x)\frac{dx}{dt}\\2\sqrt{10125}\frac{dD}{dt}=-2(90-45)(31)\\\frac{dD}{dt}=\frac{-2(45)(31)}{2\sqrt{10125}} =-13.86ft/s$

Thus, when the batter is halfway to first base, the distance between second base and the batter is decreasing at the rate of about 13.86 ft/sec.

4 0

3 years ago