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Setler [38]
3 years ago
8

Jane left the school and started to bike along the road at a rate of 12 mph. Her friend Sally left the school 10 minutes after J

ane, biking on the same road at a rate of 15 mph. How long will it take Sally to catch up with Jane?
Mathematics
1 answer:
Artyom0805 [142]3 years ago
3 0

Answer:

8 minutes if Jane was assumed to be stationary

Step-by-step explanation:

The question is on relative speed

First find the distance covered by Jane when Sally left school

Speed=Distance/Time ⇒⇒ Distance=Time×Speed

Time=10minute=10/60 hrs

Jane's speed= 12mph

Distance covered by Jane when Sally left school was= 12 ×10/60 = 2miles

So, when Sally left school, Jane was 2 miles away. To find the time Sally requires to catch up with Jane;

Time=Distance/speed

Time of meeting =2/15 hrs ⇒⇒ 2/15 × 60 =8minutes

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Step-by-step explanation:

Here in this question, we want to know the shortest height with which boxes of 12 inches tall staked will be the same height with which boxes of 18 inches staked beside it

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