Answer:
The probability that a student plays either basketball or soccer is 19% or 0.19.
Step-by-step explanation:
Let A be the event that student play basketball and B be the event that student play soccer.


It is given that 6 students play on both teams.

We have to find the probability that a student plays either basketball or soccer.



Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.
Answer:
Choice A. (10, -1)
Choice B. (-8, 9)
Choice D. (6, -3)
Step-by-step explanation:
If we plug the coordinates of point A into the inequality, then we get,
x+y > -2
10 + (-1) > -2
9 > -2
That last inequality is a true statement since 9 is to the right of -2 on the number line. That means (10,-1) is a solution. Choice A is one of the answers.
Choices B and D are also answers for similar reasons.
Something like choice C is not a solution because
x+y > -2
-1+(-9) > -2
-10 > -2
Which is false.
You should find that choice E is false as well.
If you graphed the inequality and all of the points mentioned (see below), then you can visually confirm the answers. Notice how points A, B and D are in the blue shaded region which is the solution set.
The point E on the boundary does not count as a solution. This is due to the lack of "or equal to" portion of the inequality sign. That visually shows point E is not a solution. Point C isn't a solution either as it's nowhere near the blue shaded region.
1,2,7,14 would be your answer :)
sheet me don't know my friend
Answer:
18
Step-by-step explanation:
=2(cot²A+1)
=2cosec²A. [` . ` cot²A+1=cosec²A] =2(1/sinA)²
[' . 'cosecA=1/sinA]
=2×3²/1
=2cot²a+2=2×8+2=16+2=18